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Pachacha [2.7K]
3 years ago
13

The electron configuration for Helium (He) is shown below. 1s2 Which diagram shows the correct distribution of electrons in the

electron shells of a helium atom? A gray circle labeled 1 P 0 N is surrounded by a concentric circle with one gray dot at the north position. A gray circle is labeled 5 P 6 N. It is surrounded by two concentric circles. The inner circle has gray dots at the north and south positions. The outer circle has three evenly spaced dots; none of these align with the dots in the inner circle. A gray circle is labeled 2 P 2 N. A concentric circle surrounding it has two gray dots, at the north and south positions. A gray circle is labeled 6 P 6 N is surrounded by two concentric circles. The inner circle has dots at the north and south positions; the outer circle has dots at the north, south, east, and west positions.
Mathematics
2 answers:
aksik [14]3 years ago
8 0

Answer:

A

Step-by-step explanation:

AURORKA [14]3 years ago
7 0

Answer:

what is the question comments me

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How many solutions does x²+3x=3 have?
aev [14]

Answer:

2 (real) solutions.

Step-by-step explanation:

A quadratic always has two solutions, whether they are real or complex.

Sometimes the solution is complex, involving complex numbers (2 complex), sometimes they are real and distinct (2 real), and sometimes they are real and coincident (still two real, but they are the same).

In the case of

x^2+3x = 3, or

x² + 3x -3 = 0

we apply the quadratic formula to get

x =  (-3 +/- sqrt(3^2+4(1)(3))/2

to give the two solutions

{(sqrt(21)-3)/2, -(sqrt(21)+3)/2,}

both of which are real.

4 0
3 years ago
What is x+3y=6 what is the x
Ymorist [56]
X=-3y+6 That is the answer.
3 0
3 years ago
What times 1/10 equals 0.047
Zina [86]

Answer:

.47

Step-by-step explanation:

1/10= .1

0.0.47/.1=.47

-1 x .47=0.47

5 0
3 years ago
Read 2 more answers
Find a solution x = x(t) of the equation x′ + 2x = t2 + 4t + 7 in the form of a quadratic function of t, that is, of the form x(
Temka [501]
The particular quadratic solution to the ODE is found as follows:

x=at^2+bt+c
x'=2at+b

(2at+b)+2(at^2+bt+c)=t^2+4t+7
2at^2+(2a+2b)t+(b+2c)=t^2+4t+7

\begin{cases}2a=1\\2(a+b)=4\\b+2c=7\end{cases}\implies a=\dfrac12,b=\dfrac32,c=\dfrac{11}4

Note that there's also the fundamental solution to account for, which is obtained from the characteristic equation for the ODE:

x'+2x=0\implies r+2=0\implies r=-2

so that x_c=Ce^{-2t} is a characteristic solution to the ODE, and the general solution would be

x=Ce^{-2t}+\dfrac{t^2}2+\dfrac{3t}2+\dfrac{11}4
4 0
4 years ago
Financial mathematics (see picture)
Paraphin [41]

Answer:

i think it's the answer in the pic I have send you okk see and mark me brainliest answer okk thanks

6 0
3 years ago
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