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Liula [17]
3 years ago
14

Plzzzzzzzzzzzzzzzzzzzzzzzzzzzzzz helpppppppppppppppp-3 1/5 ÷2 1/5

Mathematics
1 answer:
Alla [95]3 years ago
4 0

Answer:

−16×5 / 5×11

= -16/11

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If anyone is good at grade 8 math problems pls help answer these questions thanks!! :DD
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Answer:

53 Meters.

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34*34 + 41*41 = 2837.

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The gross weight of a truck containing 30 pigs is 8 tons 1,123 pounds and 6 ounces. The average weight of one pig is 95 pounds 1
irakobra [83]

Answer: The net weight of the pigs of the truck is 1 ton 868 pounds 12 ounces.

The weight of the empty truck is 7 tons 254 pounds 10 ounces.

Step-by-step explanation:

Since we have given that

The gross weight of a  truck containing 30 pigs = 8 tons 1123 pounds 6 ounces

Average weight of one pig = 95 pounds 10 ounces

Now,

We know that

1\text{ pound}=16\text{ ounces}

So,

\text{Gross weight of truck containing 30 pigs}\\=8\text{ tones }1123\times 16+6\text{ ounces}\\=8\text{ tons }17974\text{ ounces}

Similarly,

\text{ average weight of one pig }\\=95\times 16+10\text{ ounces}\\=1530\text{ ounces}

So, Net weight of the pigs in the truck

1530\times 30\\ =45900\text{ ounces}\\\\=\frac{45900}{16}\\\\=2868\text{ pounds }12\text{ ounces}\\\\=1\text{ ton }868\text{ pounds }12\text{ ounces }

So, the net weight of the pigs of the truck is 1 ton 868 pounds 12 ounces.

Now, we'll find the weight of the empty truck is given by

\text{Gross weight of a truck containing} -\text{ Net weight of pigs in the truck}\\=8\text{ tons}1123\text{ pounds}6\text{ ounces}-1\text{ton }868\text{ pounds }12\text{ounces}\\=(8\times 2000\times 16+1123\times 16+6)-(1\times 2000\times 16+868\times 16-12)\\=273974\text{ ounces}-45900\text{ ounces}\\=228074\text{ounces }\\=7\text{ tons }254\text{ pounds }10\text{ ounces}

Hence, the weight of the empty truck is 7 tons 254 pounds 10 ounces .


4 0
3 years ago
Find the perimeter of the<br> polygon if ZB = ZD.
Butoxors [25]

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