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Vadim26 [7]
3 years ago
15

The graph below plots a function f(x):

Mathematics
1 answer:
ASHA 777 [7]3 years ago
3 0

Answer:

40 units per sec

Step-by-step explanation:

The average rate of change in this case is the change in y over the first three seconds (which is 220 - 100, or 120) divided by the elapsed time (which is 3 seconds).

                             120

Thus, we have ------------ = 40 units per sec

                               3

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Maksim231197 [3]

Step-by-step explanation:

an = a1 + (n - 1)d \\ d = a2 - a1 \\ a1 = 3 \\ a2 =  - 15 \\ d =  - 15 - 3 =  - 18

a13 = 3 + (12)  \times ( - 18) \\ a13 = 3 - 216  \\ a13 =  - 213

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2 years ago
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marin [14]

Answer:

Step-by-step explanation:

From the table attached,

x-intercept of the linear function is, the value of 'x' when f(x) = 0  

x = 3 [x-intercept]

Function 'g' is the sum of 2 and the cube root of the sum of three time x and 1.

g(x) = 2+\sqrt[3]{3x+1}

For x-intercept,

g(x) = 0

2+\sqrt[3]{3x+1}=0

3x + 1 = (-2)³

3x + 1 = -8

3x = -8 - 1

3x = -9

x = -3

Therefore, the x-intercept of function 'f' is different or greater than the x-intercept of function g.  

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Answer:

Step-by-step explanation:

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Rory's battery was full at 6:00 a.M, or t = 0. Which times could Rory's phone have been plugged into the charger? Select three o
Taya2010 [7]

Complete question:

Rory records the percentage of battery life remaining on his phone throughout a day. The graph represents the percentage of battery life remaining after a certain number of hours.

Rory’s battery was full at 6:00 a.m, or t = 0. Which times could Rory's phone have been plugged into the charger? Select three options.

12:00 p.m.

3:00 p.m.

5:00 p.m.

8:00 p.m.

11:00 p.m.

The graph is attached

Answer:

3:00 p.m

5:00 p.m

11:00 p.m

Step-by-step explanation:

From the graph, there are rise times, fall times and there are times the movement is steady (no rise or fall).

The rise time represents the time the phone was plugged. The fall time represents when the charger has been unplugged so the battery level starts depreciating. When it is constant, it means the battery level is at 100 but the charger is still connected to the phone.

We are told at initial condition, time was 6 a.m (t = 0). To get the exact time, we are to add the initial condition, i.e 6

From the graph, the times the phone could have been plugged are 8:00 to 12:00 hrs and 16:00 to 20:00 hrs.

Converting from 24 hr to 12 hr time, we have:

6 + 8hrs = 14:00 = 2:00 p.m

6 + 9hrs = 15:00 = 3:00 p.m

6 + 10 hrs = 16:00 = 4:00 p.m

6 + 11 hrs = 17:00 = 5:00 p.m

6 + 12 hrs = 18:00 = 6:00 p.m

6 + 16 hrs = 22:00 = 10:00 p.m

6 + 17 hrs = 23:00 = 11:00 p.m

6 + 18 hrs = 00:00 = 12:00 am

6 + 19 = 1 : 00 = 1:00 a.m

6 + 20 = 2:00 = 2:00 a.m

From the options given in the question, we have:

3:00 p.m; 5:00 p.m; 11:00 p.m

Therefore, times could Rory's phone have been plugged into the charger are:

3:00 p.m

5:00 p.m

11:00 p.m

5 0
3 years ago
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