To prove a similarity of a triangle, we use angles or sides.
In this case we use angles to prove
∠ACB = ∠AED (Corresponding ∠s)
∠AED = ∠FDE (Alternate ∠s)
∠ABC = ∠ADE (Corresponding ∠s)
∠ADE = ∠FED (Alternate ∠s)
∠BAC = ∠EFD (sum of ∠s in a triangle)
Now we know the similarity in the triangles.
But it is necessary to write the similar triangle according to how the question ask.
The question asks " ∆ABC is similar to ∆____. " So we find ∠ABC in the prove.
∠ABC corressponds to ∠FED as stated above.
∴ ∆ABC is similar to ∆FED
Similarly, if the question asks " ∆ACB is similar to ∆____. "
We answer as ∆ACB is similar to ∆FDE.
Answer is ∆ABC is similar to ∆FED.
Answer:
Step-by-step explanation:
4√3
Answer:
Step-by-step explanation:
Quadrant II is the top left cornered <em>square</em>, so this coordinate is the one you would pick.
I am joyous to assist you anytime.
Answer:
21 + 14x - 56 - 42x + 168
= 133 - 28x
Step-by-step explanation:
Answer:
Step-by-step explanation:
You are trying to find the value of K, so to do that you need to get k by itself (example : K= 3-5 instead of K+5= 3)
So in 1a i would simplify 7k-3k= 4k
then 4k=11
now to get rid of the 4 and get the k alone- you DIVIDE 4k by 4 and divide 11 by 4 cause you need to do it on both sides of the equation, it should look like this.
4k= 11
- = -
4 4
(4k over 4 and 11 over four)
so the answer is k = 2.75 cause 11/4 = 2.75
