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3 years ago

Answer choices a. -4/3 b. -3/4 c. 3/4 d. 4/3

Mathematics

1 answer:

Bingel [31]3 years ago

7 0

Answer:

Step-by-step explanation:

(0, 1) (4, -2)

(-2 - 1)/(4 -0) = -3/4

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V+8w=4v,for v<br><br> -m+5n=-2, for n

jok3333 [9.3K]

Answer:

v = 8w/3,
n = (m - 2)/5.

---------------------------

<h3>Given equations</h3>

v + 8w = 4v and - m + 5n = - 2

<h3>Solve the first equation for v</h3>

v + 8w = 4v
4v - v = 8w
3v = 8w
v = 8w/3

<h3>Solve the second equation for n</h3>

- m + 5n = - 2
5n = m - 2
n = (m - 2)/5

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1 year ago

Read 2 more answers

F(x)=x^2-2x-7 <br> given the polynomial function find f(-5)

UkoKoshka [18]

Answer:

f(-5)=28

Step-by-step explanation:

f(x)=x²-2x-7

f(-5) means that we have to replace x by -5.

f(-5)=(-5)²-2(-5)-7=25+10-7=25+3=28

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3 years ago

2. For every orange there

baherus [9]

Answer:

The equivalent ratios are B and C.

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3 years ago

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Consider a large shipment of 400 refrigerators, of which 40 have defective compressors. If X is the number among 15 randomly sel

Vlad [161]

Answer:

The required probability is 0.94

Step-by-step explanation:

Consider the provided information.

There are 400 refrigerators, of which 40 have defective compressors.

Therefore N = 400 and X = 40

The probability of defective compressors is:

$\frac{40}{400}=0.10$

It is given that If X is the number among 15 randomly selected refrigerators that have defective compressors,

That means n=15

Apply the probability density function.

$P(X=x)=^nC_xp^x(1-p)^{n-x}$

We need to find P(X ≤ 3)

$P(X\leq3) =P(X=0)+P(X=1)+P(X=2)+P(X=3)\\P(X\leq3) =\frac{15!}{15!}(0.1)^0(1-0.1)^{15}+\frac{15!}{14!}(0.1)^1(1-0.1)^{14}+\frac{15!}{13!2!}(0.1)^2(1-0.1)^{13}+\frac{15!}{12!3!}(0.1)^3(1-0.1)^{12}\\$

$P(X\leq3) =0.944444369992\approx 0.94$

Hence, the required probability is 0.94

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3 years ago

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ziro4ka [17]

Answer:

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3 years ago