3 years ago

Hurry please

Mathematics

2 answers:

nadya68 [22]3 years ago

3 0

Answer:

she will have $169.74

Step-by-step explanation:

-Dominant- [34]3 years ago

3 0

She will have 169.6 just trust me

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Quadrilateral ABCD has vertices A(1,0) B(5,0) C (7,2) D(3,2). Use slope to prove that ABCD is a parallelogram.

Galina-37 [17]

Answer:

$AD \parallel BC$

$AB \parallel CD$

Step-by-step explanation:

The vertices of quadrilateral ABCD are A(1,0) B(5,0) C (7,2) D(3,2).

The slope of side AB is

$M_{AB}=\frac{0-0}{5-1} =\frac{0}{4}=0$

The slope of side BC is

$M_{BC}=\frac{2-0}{7-5} =\frac{2}{2}=1$

The slope of side CD is

$M_{CD}=\frac{2-2}{3-7} =\frac{0}{-4}=0$

The slope of AD is

$M_{AD}=\frac{2-0}{3-1} =\frac{2}{2}=1$

$AD \parallel BC$

$AB \parallel CD$

We see that the opposite sides of the quadrilateral ABCD are equal.

Hence the quadrilateral is a parallelogram

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3 years ago

Are we finding the area or circumstances?

lidiya [134]

Answer:

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How do I do this?<br> Im stuck on what to do

Nastasia [14]

CD and DE are equal distance so their equations are equal:
2x+7 = 4(x-3)
2x+7 = 4x-12
Subtract 2x from both sides
7 = 2x-12
Add 12 to both sides
19 = 2x
9.5 = x
Now that u have x just plug it into the equation for DE
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26 is the answer

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(4, -9) is it a solution yes or no ? <br>

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