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2 years ago

ANSWER TO BE NAMED BRAINLIEST GET A THANK YOU A FOLLOW AND 25 PPTS

Mathematics

1 answer:

Svet_ta [14]2 years ago

8 0

Answer:

192 cm^3

Step-by-step explanation:

Volume for rectangular prism is V=l*w*h

V=8*4*6=32*6=192

So volume is 192 cm^3

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Solve the system of linear equations by substitution. 2x=y−10 x+7=y

Vedmedyk [2.9K]

Answer:

(-3, 4)

Step-by-step explanation:

2x = y - 10 (y = x +7) so

2x = x +7 - 10

2x = x -3

x = -3

-3 + 7 = y

4 = y

5 0

3 years ago

Read 2 more answers

In the United States, voters who are neither Democrat nor Republican are called Independent. It is believed that 11% of voters a

Radda [10]

Answer:

a) 0.0214 = 2.14% probability that none of the people are Independent.

b) 0.8516 = 85.16% probability that fewer than 6 are Independent.

c) 0.8914 = 89.14% probability that more than 2 people are Independent.

Step-by-step explanation:

For each people, there are only two possible outcomes. Either they are independent, or they are not. For each person asked, the probability of them being Independent voters is the same. This means that we use the binomial probability distribution to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

In which $C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And p is the probability of X happening.

It is believed that 11% of voters are Independent.

This means that $p = 0.11$

A survey asked 33 people to identify themselves as Democrat, Republican, or Independent.

This means that $n = 33$

A. What is the probability that none of the people are Independent?

This is P(X = 0). So

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 0) = C_{33,0}.(0.11)^{0}.(0.89)^{33} = 0.0214$

0.0214 = 2.14% probability that none of the people are Independent.

B. What is the probability that fewer than 6 are Independent?

This is

$P(X < 6) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3) + P(X = 4) + P(X = 5)$

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 0) = C_{33,0}.(0.11)^{0}.(0.89)^{33} = 0.0214$

$P(X = 1) = C_{33,1}.(0.11)^{1}.(0.89)^{32} = 0.0872$

$P(X = 2) = C_{33,2}.(0.11)^{2}.(0.89)^{31} = 0.1724$

$P(X = 3) = C_{33,3}.(0.11)^{3}.(0.89)^{30} = 0.2202$

$P(X = 4) = C_{33,4}.(0.11)^{4}.(0.89)^{29} = 0.2041$

$P(X = 5) = C_{33,5}.(0.11)^{5}.(0.89)^{28} = 0.1463$

$P(X < 6) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3) + P(X = 4) + P(X = 5) = 0.0214 + 0.0872 + 0.1724 + 0.2202 + 0.2041 + 0.1463 = 0.8516$

0.8516 = 85.16% probability that fewer than 6 are Independent.

C. What is the probability that more than 2 people are Independent?

This is:

$P(X \geq 2) = 1 - P(X < 2)$

In which

$P(X < 2) = P(X = 0) + P(X = 1)$

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 0) = C_{33,0}.(0.11)^{0}.(0.89)^{33} = 0.0214$

$P(X = 1) = C_{33,1}.(0.11)^{1}.(0.89)^{32} = 0.0872$

$P(X < 2) = 0.0214 + 0.0872 = 0.1086$

$P(X \geq 2) = 1 - P(X < 2) = 1 - 0.1086 = 0.8914$

0.8914 = 89.14% probability that more than 2 people are Independent.

8 0

2 years ago

olivia goes to egypt and saw a model of a pyramid. She enlarged it using a scale factor of 1.2. What will be the perimeter and a

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Olivia applied the scale factor to the measurements of the model she saw. We need to know those in order to calculate the new ones.

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3 years ago

A coin collection is made up of 34 coins, all nickels and dimes. The total value of the collection is $1.90. How many nickels ar

wel

Answer:

Hey There the Answer to this is x = nickels

y= dimes

x + y = 34

.05x + .10y= $1.90

-.10x - .10y = -3.40

-.05x + .10y = 1.90

-.05x = -1.50

x = 30 nickels

30 + y = 34

y = 4 dimes

(3,4) And that you get the answer.

Hope it helps!

6 0

3 years ago

The subject of the formula below is y.

Anna007 [38]

Answer:

x = y + 8

Step-by-step explanation:

Given

y = x - 8 ( add 8 to both sides )

y + 8 = x

4 0

2 years ago

Read 2 more answers