1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
ch4aika [34]
3 years ago
10

A cell phone manufacturer claims that the average battery life of its newest flagship smartphone is exactly 20 hours. Javier bel

ieves the mean battery life is less than 20 hours. He tests this claim by selecting a random sample of 33 phones of this model. avier found that the sample mean battery life is 19.5 hours with a sample standard deviation of 1.9 hours. The test statistic t for a hypothesis test of H0:μ=20 versus Ha:μ<20 is t≈−1.51 with 32 degrees of freedom. If 0.05
Select all that apply:

(A) Reject the null hypothesis that the true population mean battery life of the smartphone is equal to 20 hours.
(B) Fail to reject the null hypothesis that the true population mean battery life of the smartphone is equal to 20 hours.
(C) There is not enough evidence at the α=0.05 level of significance to suggest that the true population mean battery life of the smartphone is less than 20 hours.
(D) There is enough evidence at the α=0.05 level of significance to support the claim that the true population mean battery life of the smartphone is not equal to 20 hours.
Mathematics
1 answer:
adelina 88 [10]3 years ago
5 0

Answer:

(B) Fail to reject the null hypothesis that the true population mean battery life of the smartphone is equal to 20 hours.

(C) There is not enough evidence at the α=0.05 level of significance to suggest that the true population mean battery life of the smartphone is less than 20 hours.

Step-by-step explanation:

1) Data given and notation    

\bar X=19.5 represent the battery life sample mean  

s=1.9 represent the sample standard deviation    

n=33 sample size    

\mu_o =20 represent the value that we want to test  

\alpha=0.05 represent the significance level for the hypothesis test.    

t would represent the statistic (variable of interest)    

p_v represent the p value for the test (variable of interest)    

2) State the null and alternative hypotheses.    

We need to conduct a hypothesis in order to check if the mean battery life is less than 20 :    

Null hypothesis:\mu \geq 20    

Alternative hypothesis:\mu < 20    

Since we don't know the population deviation, is better apply a t test to compare the actual mean to the reference value, and the statistic is given by:    

t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}} (1)    

t-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".    

3) Calculate the statistic    

We can replace in formula (1) the info given like this:    

t=\frac{19.5-20}{\frac{1.9}{\sqrt{33}}}=-1.51    

4) P-value    

First we need to calculate the degrees of freedom given by:

df=n-1=33-1=32

Since is a one-side lower test the p value would be:    

p_v =P(t_{(32)}    

5) Conclusion    

If we compare the p value and the significance level given \alpha=0.05 we see that p_v>\alpha so we can conclude that we have enough evidence to FAIL to reject the null hypothesis, so we can conclude that the average battery life it's not significantly different less than 20 hours at 5% of signficance. If we analyze the options given we have:

(A) Reject the null hypothesis that the true population mean battery life of the smartphone is equal to 20 hours. FALSE, we FAIL to reject the null hypothesis.

(B) Fail to reject the null hypothesis that the true population mean battery life of the smartphone is equal to 20 hours. TRUE, we fail to reject the null hypothesis that the mean would be 20 or higher .

(C) There is not enough evidence at the α=0.05 level of significance to suggest that the true population mean battery life of the smartphone is less than 20 hours.  TRUE, we FAIL to reject the null hypothesis that the mean is greater or equal to 20 hours, so we reject the alternative hypothesis that the mean is less than 20 hours.

(D) There is enough evidence at the α=0.05 level of significance to support the claim that the true population mean battery life of the smartphone is not equal to 20 hours. FALSE the claim is not that the mean is different from 20. The real claim is: "Javier believes the mean battery life is less than 20 hours".

You might be interested in
The sides of a quadrilateral are in ratio 1:2:3:4 if the perimeter is 40cm. find the length of each sides​
m_a_m_a [10]
1:2:3:4= 4:8:12:16
Explanation:
Add 1,2,3,4 then divide by 40 which gives you 4.
Then put those in the ratios given :)
5 0
3 years ago
Sinxcosxtanx=1-cos^2x
ycow [4]

Step-by-step explanation:

sin  x \: cos  x \: tanx = 1 -  {cos}^{2} x \\ LHS \\= sin  x \: cos  x \: tanx \\  =sin  x \: cos  x \: \times  \frac{sin  x}{cos  x}  \\  = sin  x \: \times  \frac{sin  x}{1} \\  ={sin}^{2}  x \\  = 1 -  {cos}^{2} x \\  = RHS \\  \therefore \: sin  x \: cos  x \: tanx = 1 -  {cos}^{2} x \\ Hence \: Proved.

7 0
3 years ago
Determine the equations you would use to represent the situation.
ASHA 777 [7]

Answer:

You sold 20 student tickets.

Step-by-step explanation:

Given that:

Total tickets sold = 27

Total amount collected = $170

Cost of student ticket = $5

Cost of adult ticket = $10

Let,

x be the number of students tickets sold

y be the number of adult tickets sold

x+y = 27          Eqn 1

5x+10y=170     Eqn 2

Multiplying Eqn 1 by 10

10(x+y=27)

10x+10y=270     Eqn 3

Subtracting Eqn 2 from Eqn 3

(10x+10y)-(5x+10y)=270-170

10x+10y-5x-10y=100

5x=100

Dividing both sides by 5

\frac{5x}{5}=\frac{100}{5}\\x=20

Hence,

You sold 20 student tickets.

3 0
3 years ago
I don’t understand this, someone help?
tekilochka [14]
From what I can see, it might be wanting you to find the distance of the lines connecting the 2 points. Use then distance formula to do that.
7 0
3 years ago
alden walked 2 miles in 3/4 hours .kira walked 1 3/4 miles in 30 minutes? who walked at a faster rate?
MissTica

Kira did because by the time she walked for 45 minutes, she would be above 2 miles

7 0
3 years ago
Other questions:
  • Let A = {1, 2, 3, 4, 5, 6, 7, 8, 9}. n distinct integers will be chosen from A. How big does n have to be
    12·1 answer
  • What figure can be created using the net
    13·1 answer
  • How to write 0.924 in two other forms
    6·1 answer
  • Write an algebraic expression for each verbal expression <br><br> Nine divided by x
    11·1 answer
  • Is the number 65.4349224... rational or irrational? Explain.
    15·3 answers
  • Find the square root of 3 upon 5 upto 2 decimal places​
    11·1 answer
  • Solve 3x+4x= totally not free pointz
    14·2 answers
  • 5. If "h" is positive how does the parabola move? If negative?
    7·1 answer
  • In a shop, a TV has a normal price of £500
    11·1 answer
  • Which expression is equivalent to 1 2 + (−7) − 2 1 4 − (−2
    15·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!