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Vaselesa [24]
3 years ago
15

Solve the linear system of equations using the linear combination method.

Mathematics
1 answer:
yawa3891 [41]3 years ago
6 0
Hello!

4x - 9y = 20
2x - 6y = 16

You first need one of the variables have the same coefficient

We can do this by multiplying the second equation by 2

4x - 12y = 32

Subtract the equations to get rid of x

4x - 9y = 20
4x - 12y = 32

3y = -12

Divide both sides by 3

y = -4

Put y into one of the original equations

2x - 6(-4) = 16

Multiply

2x - -24 = 16

We you subtract a negative it is the same as addding

2x + 24 = 16

Subtract 24 from both sides

2x = -8

Divide both sides by 2

x = -4

The answers are x = -4 and y = -4

Hope this helps!
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A differential equation is an equation involving an unknown function and its derivatives. Consider the differential equation 0.
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Answer: hi your question is poorly written below is the correct question

answer :

a) y1 = Asint,   y'1 = Acost  , y"1 = -Asint

b) y2 = Bcost,   y'2 = Bsint , y"2 = - Bcost

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Step-by-step explanation:

y" + y = 0

Proves

a) y1 = Asint,   y'1 = Acost  , y"1 = -Asint

b) y2 = Bcost,   y'2 = Bsint , y"2 = - Bcost

c) y3 = y1 + y2 ,   y'3 = y'1 + y'2,  y"3 = y"1 + y"2

∴ y"1 + y1 = -Asint + Asint

  y"2 + y2 = -Bcost + Bcost

  y"3 - y3 = y"1 + y"2 - ( y1 + y2 )

               = y"1 - y1 + y"2 - y2  

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Hence we can conclude that y = Asint + B cost satisfies the equation for any constant A and B

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Step-by-step explanation:

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