Let us say that:
a = ones
b = fives
c = twenties
So that the total money is:
1 * a + 5 * b + 20 * c = 229
=> a + 5b + 20c = 229 -->
eqtn 1
We are also given that:
c = a – 5 -->
eqtn 2
a + b + c = 30 -->
eqtn 3
Rewriting eqtn 3 in terms of b:
b = 30 – a – c
Plugging in eqtn 2 into this:
b = 30 – a – (a – 5)
b = 35 – 2a -->
eqtn 4
Plugging in eqtn 2 and 4 into eqtn 1:
a + 5(35 – 2a) + 20(a – 5) = 229
a + 175 – 10a + 20a – 100 = 229
11a = 154
a = 14
So,
b = 35 – 2a = 7
c = a – 5 = 9
Therefore there are 14 ones, 7 fives, and 9 twenties.
![\sqrt[3]{a} = {a}^{m} \\ = > { a}^{ \frac{1}{3} } = {a}^{m} \\ = > m = \frac{1}{3}](https://tex.z-dn.net/?f=%20%5Csqrt%5B3%5D%7Ba%7D%20%20%3D%20%20%7Ba%7D%5E%7Bm%7D%20%20%5C%5C%20%20%3D%20%20%3E%20%20%7B%20a%7D%5E%7B%20%5Cfrac%7B1%7D%7B3%7D%20%7D%20%20%3D%20%20%7Ba%7D%5E%7Bm%7D%20%20%5C%5C%20%20%3D%20%20%3E%20m%20%3D%20%20%5Cfrac%7B1%7D%7B3%7D%20)
<u>Answer</u><u>:</u>
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Hope you could understand.
If you have any query, feel free to ask.
The given triangle is
To solve for PR, we have to use the sine function which is equivalent to the ratio between the opposite leg and the hypothenuse.

<h2>Hence, PR is 37.04 mm long, approximately.</h2>
Answer:
(7a^2 + 8b^2 + 5ab) (7a^2 + 8b^2 - 5ab)
Step-by-step explanation:
Dado que ambos términos son cuadrados perfectos, puede factorizar utilizando la fórmula de la diferencia de cuadrados, a^2 - b^ 2 = (a + b) (a - b), donde a = 7a^2 + 8b^2 y b = 5ab.
English: Since both terms are perfect squares you can factor using the difference of squares formula, a^2 - b^2 = (a + b)(a - b), where a = 7a^2 + 8b^2 and b = 5ab.
Answer:
P= 7/9 miles
A= (7/18) miles²
Step-by-step explanation:
Length 'l' = (1/6) mile
Width 'w'= (2/9) mile
Perimeter 'P' is given by:
'P' = 2l + 2w => 2(1/6) + 2(2/9)
P= 7/9 miles
Area 'A' is given by:
A= l x w =(1/6) x (2/9) = (7/18) miles²