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egoroff_w [7]
3 years ago
6

How would you solve this?? i need to understand the process to theses types of problems!!

Mathematics
1 answer:
Evgen [1.6K]3 years ago
8 0

Answer:

  CD = 10√3

Step-by-step explanation:

First of all, you need to understand the terms. The <em>incenter</em> is the center of an inscribed circle. Such a circle is tangent to all three sides of the triangle at points B, D, and F. The distances BG, DG, and FG are each the radius of the circle.

The diagram shows FG = 22, so that is also the measure of DG. This gives you two of the three sides of right triangle CDG, so you know enough to apply the Pythagorean theorem.

  CG^2 = CD^2 + DG^2

  28^2 = CD^2 + 22^2

  300 = CD^2 . . . . . . . . subtract 22^2

  10√3 = CD . . . . . . . . . take the positive square root

The measure of CD is 10√3.

_____

The process is to understand the geometric relationships and what they mean regarding the algebraic relationships. Then you use the algebraic relationships to write equations that let you find the unknowns you seek.

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a small business owner ships jars of homemade honey. four jars weigh a total of 7.4 pounds . how much will 24 jars weigh?
amm1812

Step-by-step explanation:

7.4÷4= 1.85

1 jar weighs 1.85 pounds

1.85×24= 44.4 pounds

another way:

7.4x6= 44.4pounds

3 0
3 years ago
A robot vacuum advertises that it can clean a 120-square-foot room in 1/2 an hour. How many square feet could the robot vacuum c
sertanlavr [38]

Answer: 240 square foot room

Step-by-step explanation: They ask for how many square feet in 1 hour which is double the 1/2 hour. So, just do 120x2=240 to get your answer! (Don’t forget to label ,square-feet,)

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3 years ago
5. GEOMETRY The volume of a rectangular pyramid is one third the product of the area of its base and its height. Find
tatuchka [14]

Answer:

x³ + 7x² + 15x + 9

Step-by-step explanation:

Given that the volume (V) of a rectangular pyramid is

V = \frac{1}{3} A h ( A is the area of base and h the height ), then

V = \frac{1}{3} (3x² + 12x + 9)(x + 3) ← factor out 3 from A

   = \frac{1}{3} × 3(x² + 4x + 3)(x + 3)

   = (x² + 4x + 3)(x + 3)

Each term in the second factor is multiplied by each term in the first factor, that is

x² (x + 3) + 4x(x + 3) + 3(x + 3) ← distribute parenthesis

= x³ + 3x² + 4x² + 12x + 3x + 9 ← collect like terms

= x³ + 7x² + 15x + 9

Thus the expression for the volume is

V = x³ + 7x² + 15x + 9

4 0
3 years ago
In the shop, 27/32 of the jackets have zippers. Of the jackets with zippers, 8/9 have hoods. What fraction have hoods
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Answer:

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4 0
4 years ago
Suppose that P(n) is a propositional function. Determine for which nonnegative integers n the statement P(n) must be true if a)
wel

Solution :

a). $P(0)$ is true

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         $P(2+2)=P(4)$ is true

          $P(4+2)=P(6)$ is true.

Therefore, we see that $P(n)$ is true for all the even integers : $\{0, 2,4,6,...\}$

b). $P(0)$ is true

Then ,$P(0+3)=P(3)$ is true.

         $P(3+3)=P(6)$ is true

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Therefore, we see that $P(n)$ is true for all the multiples of 3 : $\{0, 3,6,9,12,...\}$

c). $P(0)$ and $P(1)$ is true, then $P(0+2)=P(2)$ is true

$P(1)$ and $P(2)$ is true, then $P(1+2)=P(3)$ is true.

$P(2)$ and $P(3)$ is true, then $P(2+2)=P(4)$ is true.

So, we observe that  $P(n)$ is true for all the non- negative integers : $\{0, 1,2,3,4,5,6,...\}$.

d). $P(0)$ is true,

   So, $P(0+2)$ and $P(0+3)$ is true or $P(2)$ and $P(3)$ is true.

   Now,   $P(2)$ is true.

Again, $P(2+2)$ and $P(2+3)$ is true or $P(4)$ and $P(5)$ is true.

   Now, $P(3)$ is true.

Again, $P(3+2)$ and $P(3+3)$ is true or $P(5)$ and $P(6)$ is true.

Thus,

$P(n)$ is true for all the non- negative integers except 1 : $\{0, 2,3,4,5,6,...\}$.

3 0
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