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1 year ago

Write an equation of a line that is perpendicular to the line y-8=4(x-5)

Mathematics

1 answer:

vesna_86 [32]1 year ago

8 0

Equation of the new perpendicular line is $y - y_{1} = -\frac{1}{4} (x- x_1)$

How to calculate the new perpendicular line?

The given equation is:

y- 8=4 (x-5)

This equation is of the point- slope form

$y- y_{1}= m(x-x_{1})$

y - 8 = 4( x-5 )

So, the slope (m) is m = 4

The points $(x_1,y_1) = (5,8)$

Hence, slope of the line perpendicular to the given line is

m = $-\frac{1}{4}$

The equation of the new perpendicular line is :

$y- y_{1}= m(x-x_{1})\\\\y - y_{1} = -\frac{1}{4} (x- x_1)$

Since the points through which the line passes is not given.

To learn more about point - slope form, refer:

brainly.com/question/6497976

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Write an equation of a line that is perpendicular to the line y-8=4(x-5)​

Write an equation of a line that is perpendicular to the line y-8=4(x-5)