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3 years ago

Solve 5x – 6y = –38. 3x + 4y = 0 . .

2 answers:

7 0

3x + 4y = 0
3x = -4y
x = 4y/3

5x - 6y = -38
(5*4y/3) - 6y = -38
(20y/3) - 6y = -38
(20y - 18y) / 3 = -38
2y = -114
y = -57

x = 76

horsena [70]3 years ago

7 0

Answer:

The value of x= - 4 and y = 3 .

Step-by-step explanation:

As given the equations

5x – 6y = –38

3x + 4y = 0

Multiply 5x – 6y = –38 by 3

15x - 18y = -114

Mutiply 3x + 4y = 0 by 5

15x + 20y = 0

Than the two equations are

15x - 18y = -114

15x + 20y = 0

Subtracted 15x + 20y = 0 from 15x - 18y = -114 .

15x - 15x - 18y - 20y = -114

-38y = -114

$y = \frac{114}{38}$

y = 3

Putting this value in the equation

15x + 20 × 3 = 0

15x + 60 = 0

15x = -60

$x = \frac{-60}{15}$

x = -4

Therefore the value of x= - 4 and y = 3 .

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Read 2 more answers

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strojnjashka [21]

Answer:

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$\displaystyle \textcolor{black}{2.}\:[4, -7]$

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Step-by-step explanation:

When using the Elimination method, you eradicate one pair of variables so they are set to zero. It does not matter which pair is selected:

$\displaystyle \left \{ {{2x - 3y = 9} \atop {-5x - 3y = 30}} \right.$

{2x - 3y = 9

{⅖[−5x - 3y = 30]

$\displaystyle \left \{ {{2x - 3y = 9} \atop {-2x - 1\frac{1}{5}y = 12}} \right. \\ \\ \frac{-4\frac{1}{5}y}{-4\frac{1}{5}} = \frac{21}{-4\frac{1}{5}} \\ \\ \boxed{y = -5, x = -3}$

------------------------------------------------------------------------------------------

$\displaystyle \left \{ {{x - 2y = 10} \atop {x + 3y = 5}} \right.$

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{⅔[x + 3y = 5]

$\displaystyle \left \{ {{x - 2y = 10} \atop {\frac{2}{3}x + 2y = 3\frac{1}{3}}} \right. \\ \\ \frac{1\frac{2}{3}x}{1\frac{2}{3}} = \frac{13\frac{1}{3}}{1\frac{2}{3}} \\ \\ \boxed{x = 8, y = -1}$

_______________________________________________

$\displaystyle \left \{ {{y = -3x + 5} \atop {y = -8x + 25}} \right.$

{y = −3x + 5

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$\displaystyle \left \{ {{y = -3x + 5} \atop {-\frac{3}{8}y = 3x - 9\frac{3}{8}}} \right. \\ \\ \frac{\frac{5}{8}y}{\frac{5}{8}} = \frac{-4\frac{3}{8}}{\frac{5}{8}} \\ \\ \boxed{y = -7, x = 4}$

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$\displaystyle \left \{ {{y = -x + 1} \atop {y = 4x - 14}} \right.$

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$\displaystyle \left \{ {{y = -x + 1} \atop {\frac{1}{4}y = x - 3\frac{1}{2}}} \right. \\ \\ \frac{1\frac{1}{4}y}{1\frac{1}{4}} = \frac{-2\frac{1}{2}}{1\frac{1}{4}} \\ \\ \boxed{y = -2, x = 3}$