Answer:
1/sqrt10
Step-by-step explanation:
1) Find out cosA using formula (cosA)^2+(sinA)^2=1
The module of cosA= sqrt (1- (-3/5)^2)= sqrt 16/25=4/5
So cosA=-4/5 or cosA=4/5.
Due to the condition 270degrees< A<360 degrees, 0<cosA<1 that's why cosA=4/5.
2) Find sinA/2 using a formula cosA= 1-2sinA/2*sinA/2 where cosA=4/5.
(sinA/2)^2= 0.1
sinA= sqrt 0.1= 1/ sqrt10 or sinA= - sqrt 0.1= -1/sqrt10
But 270°< A< 360°, then 270/2°<A/2<360/2°
135°<A/2<180°, so sinA/2 must be positive and the only correct answer is
sin A/2= 1/sqrt10
ANSWER: y= -4x+1
slope-intercept form is y=mx+b
to find m, which is the slope, we used
m=(y2-y1)/(x2-x1) (rise over run)
=(-15-(-3)/4-1)
= -12/3
= -4
to find b, choose one of the points and use the slope -4 and plug it in:
y=m(x)+b
-3= -4(1)+b
-3= -4+b
1=b
Answer:
$16
Step-by-step explanation:
48÷3= $16 per pair of shoe
Answer:
I'm pretty sure that is correct. 3 non collinear points always form a triangle.
