The answer to the question
Answer:
the positive slope of the asymptote = 5
Step-by-step explanation:
Given that:

Using the standard form of the equation:

where:
(h,k) are the center of the hyperbola.
and the y term is in front of the x term indicating that the hyperbola opens up and down.
a = distance that indicates how far above and below of the center the vertices of the hyperbola are.
For the above standard equation; the equation for the asymptote is:

where;
is the slope
From above;
(h,k) = 11, 100
= 100
a = 
a = 10

b = 
b = 2


y = 5x-53 , -5x -57
Since we are to find the positive slope of the asymptote: we have
to be the slope in the equation 
= 
= 5
Thus, the positive slope of the asymptote = 5
Let smaller no be x and bigger be y
- x+y=39--(1)
- 3x=y+81
- y=3x-81
- y=3(x-27)--(2)
Put it in eq(1)
- x+3(x-27)=39
- x+3x-81=39
- 4x=81+39
- 4x=120
- x=30
Now
The numbers are 9 and 30
Answer:
30
Step-by-step explanation:
6 papers per hour • 5 hours of work = 30 papers done in 5 hours.
If I need to go further, it would take 11 hours to grade all the papers because 6 • 11 = 66.