Answer:
Step-by-step explanation:
Given
The attached triangle
Required
Length AB
To do this, we make use of sine law which is represented as:
So, we have:
Make AB the subject
Answer: the rule is (x, y) → (x – 4, y + 15)
D’ in the image are (9, –8)?
x – 4= 9 y + 15= -8, so x=13, and y = - 8-15=-23
so D(13, -23)
True.
Let p1 and p2 be the two parallel planes. Let n1 be the normal vector of plane p1 (which is a vector perpendicular to the plane). If p2 is parallel to p1, then n1 is also a normal vector for p2.
Let p3 be the third secant plane, and n3 be its normal vector.
The direction vector of the intersection line of two planes is given by the cross products of their normal vectors (this is due to the fact that the cross product of two vectors is orthogonal two both of them, and that the direction vector of the intersection must be orthogonal two both normal vectors). So, the direction vectors of the two lines are:
v1 = n1 × n3
v2 = n1 × n3
The are equal. Hence, the lines are parallel.
Y = 2m + p
12 = 2m + 2
10 = 2m
5 = m
The taxi cab traveled 5 miles.
25 since 150 is equivalent to 25
