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3 years ago

Use law of sines or law of cosines to find the length of side AB Please show work !!

Mathematics

1 answer:

scoray [572]3 years ago

7 0

Answer:

$AB = 11.3$

Step-by-step explanation:

Given

The attached triangle

Required

Length AB

To do this, we make use of sine law which is represented as:

$\frac{a}{\sin(a)} = \frac{b}{\sin(b)} = \frac{c}{\sin(c)}$

So, we have:

$\frac{15}{\sin(70)} = \frac{AB}{\sin(45)}$

Make AB the subject

$AB = \frac{15}{\sin(70)} * \sin(45)$

$AB = \frac{15}{0.9397} *0.7071$

$AB = 11.3$

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90% of a number is x . What is 100% of the number? Assume x>0

mariarad [96]

Step-by-step explanation:

Let the required number be n

$\therefore \: \frac{90}{100} \times n = x \\ \\ \therefore \: \frac{9}{10} \\ \\ \therefore \:n = \frac{10}{9} x \\ \\ \therefore 100\% \: of\:n = \frac{10}{9} x \times 100\% \\ \\ = \frac{10}{9} x \times \frac{100}{100} \\ \\ = \frac{10}{9} x \\$

NOTE: A number is always 100% in itself.

3 0

3 years ago

An oblique triangular pyramid has a base area

lubasha [3.4K]

The height of the oblique triangular pyramid is 18 units if the base area of 21 square units and a volume of 126 cubic units.

<h3>What is volume?</h3>

It is defined as a three-dimensional space enclosed by an object or thing.

We know the volume of an oblique triangular pyramid is given by:

$\rm V = \dfrac{1}{3}b\times h$

Where b is the area of the base and h is the height of the pyramid.

We have b = 21 square units and V = 126 cubic units.

$\rm 126 = \dfrac{1}{3}\times21\times h$

h = 18 units

Thus, the height of the oblique triangular pyramid is 18 units if the base area of 21 square units and a volume of 126 cubic units.

Learn more about the volume here:

brainly.com/question/16788902

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5 0

2 years ago

Some bikes and trikes are on the playground. There are 7 seats and 19 wheels. How many bikes are there? How many trikes are ther

snow_tiger [21]

Okay here we go!
1. I'm a visual person so i would start by drawing circles for the wheels.
o o o o o o o o o o o o o o o o o o o
2. I tried separating them by threes
ooo ooo ooo ooo ooo ooo o
2 By two's
oo oo oo oo oo oo oo oo oo o
3. then i started to count
ooo ooo ooo ooo ooo = 15 and i still had 4 left over
oo oo = 4 and that would equal to 19 wheels!

the answer is: there are 5 trikes and 2 bicycles!!!!!
Hope that helped!
:)

6 0

3 years ago

Read 2 more answers

A car can travel 120km ik 2 hours How long will it take the car to travel 300km

ehidna [41]

It would take the car 5 hours to travel 300km.

Equation used to solve: (120÷2)×6

3 0

3 years ago

Read 2 more answers

(01.03. 106, 1.08 HC)

zlopas [31]

Answer:

A) see attached for a graph. Range: (-∞, 7]

B) asymptotes: x = 1, y = -2, y = -1

C) (x → -∞, y → -2), (x → ∞, y → -1)

Step-by-step explanation:

A graphing calculator is useful for graphing the function. We note that the part for x > 1 can be simplified:

$\dfrac{-x^2+x+2}{x^2-3x+2}=-\dfrac{(x-2)(x+1)}{(x-2)(x-1)}=-\dfrac{x+1}{x-1}\quad x\ne 2$

This has a vertical asymptote at x=1, and a hole at x=2.

The function for x ≤ 1 is an ordinary exponential function, shifted left 1 unit and down 2 units. Its maximum value of 3^-2 = 7 is found at x=1.

The graph is attached.

The range of the function is (-∞, 7].

As we mentioned in Part A, there is a vertical asymptote at x = 1. This is where the denominator (x-1) is zero.

The exponential function has a horizontal asymptote of y = -2; the rational function has a horizontal asymptote of y = (-x/x) = -1. The horizontal asymptote of the exponential would ordinarily be y=0, but this function has been translated down 2 units.

The end behavior is defined by the horizontal asymptotes:

for x → -∞, y → -2

for x → ∞, y → -1

7 0

2 years ago