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dedylja [7]
3 years ago
5

Use law of sines or law of cosines to find the length of side AB Please show work !!

Mathematics
1 answer:
scoray [572]3 years ago
7 0

Answer:

AB = 11.3

Step-by-step explanation:

Given

The attached triangle

Required

Length AB

To do this, we make use of sine law which is represented as:

\frac{a}{\sin(a)} = \frac{b}{\sin(b)} = \frac{c}{\sin(c)}

So, we have:

\frac{15}{\sin(70)} = \frac{AB}{\sin(45)}

Make AB the subject

AB = \frac{15}{\sin(70)} * \sin(45)

AB = \frac{15}{0.9397} *0.7071

AB = 11.3

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Answer:

<h3>It can be concluded that this polynomial has a degree of 2, so the equation x²+x−12=0 has exactly two root</h3>

Step-by-step explanation:

Given the quadratic polynomial  x²+x−12, the highest power in the quadratic polynomial gives its degree. The degree of this  quadratic polynomial  is therefore 2. <u>This means that the equation has exactly two solutions. </u>

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x²+x−12 = 0

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Step-by-step explanation:

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