Answer:
10
Step-by-step explanation:
the most common #is 10
You can do this in parts.
g(-3) = 3(-3) + 1 = -9 + 1 = -8
So, 5g(-3) = 5(-8) = -40.
So f(-1) + 5g(-3) = 2 - 40 = -38
Or you can do this as one big chunk.
f(-1) + 5g(-3)
![=[(-1)^2+1] + 5[3(-3) + 1] \\ = (2) + 5(-9 + 1) \\ = 2 + 5(-8) \\ = 2 - 40 \\ = -38](https://tex.z-dn.net/?f=%3D%5B%28-1%29%5E2%2B1%5D%20%2B%205%5B3%28-3%29%20%2B%201%5D%20%5C%5C%0A%3D%20%282%29%20%2B%205%28-9%20%2B%201%29%20%5C%5C%0A%3D%202%20%2B%205%28-8%29%20%5C%5C%0A%3D%202%20-%2040%20%5C%5C%20%3D%20-38)
Answer:
x = 58
Step-by-step explanation:
This question can be solved by using the exterior angle property, which states that the exterior angle of a triangle = the sum of the two opposite interior angles.
62 lies on a line, so the exterior angle is 180 - 62, or 118 degrees.
Using the EAP, we can conclude the following:
(x + 2) + (x) = 118
2x + 2 = 118
2x = 116
x = 58
Hope this helps
Answer:
<h3>
By using the distributive property the matched equivalent expressions are</h3><h3>
1) -7(-4+x)
=28-7x
</h3><h3>
2) -7(4-x)
=-28+7x
</h3><h3>
3) 7(4+x)
=28+7x
</h3><h3>
4) 7(-4-x)
=-28-7x
</h3>
Step-by-step explanation:
Given that by using the distributive property to match the given equivalent expressions.
1) Given expression is -7(-4+x)
<h3>By Distributive property a(b+c)=ab+ac</h3>
-7(-4+x)
=(-7)(-4)+(-7)(x)
=28-7x
<h3>∴ -7(-4+x)
=28-7x
</h3>
2) Given expression is -7(4-x)
<h3>By Distributive property a(b+c)=ab+ac</h3>
-7(4-x)
=(-7)(4)+(-7)(-x)
=-28+7x
<h3>∴ -7(4-x)
=-28+7x
</h3>
3) Given expression is 7(4+x)
<h3>By Distributive property a(b+c)=ab+ac</h3>
7(4+x)
=(7)(4)+(7)(x)
=28+7x
<h3>∴ 7(4+x)
=28+7x
</h3>
4) Given expression is 7(-4-x)
<h3>By Distributive property a(b+c)=ab+ac</h3>
7(-4-x)
=(7)(-4)+(7)(-x)
=-28-7x
<h3>∴ 7(-4-x)
=-28-7x
</h3>
Hence the matched equivalent expressions are
1) -7(-4+x)
=28-7x
2) -7(4-x)
=-28+7x
3) 7(4+x)
=28+7x
4) 7(-4-x)
=-28-7x
Answer:
OAB is 90°
Explanation -
Given - A circle with centre O
According to the theorem , The tangent of a circle and the line of tangency make an angle of 90°
