All categories

3 years ago

Use the distributive property to match equivalent expressions.

Mathematics

1 answer:

NeTakaya3 years ago

4 0

Answer:

<h3>By using the distributive property the matched equivalent expressions are</h3><h3>1) -7(-4+x) =28-7x </h3><h3>2) -7(4-x) =-28+7x </h3><h3>3) 7(4+x) =28+7x </h3><h3>4) 7(-4-x) =-28-7x </h3>

Step-by-step explanation:

Given that by using the distributive property to match the given equivalent expressions.

1) Given expression is -7(-4+x)

<h3>By Distributive property a(b+c)=ab+ac</h3>

-7(-4+x) =(-7)(-4)+(-7)(x)

=28-7x

2) Given expression is -7(4-x)

<h3>By Distributive property a(b+c)=ab+ac</h3>

-7(4-x) =(-7)(4)+(-7)(-x)

=-28+7x

3) Given expression is 7(4+x)

<h3>By Distributive property a(b+c)=ab+ac</h3>

7(4+x) =(7)(4)+(7)(x)

=28+7x

4) Given expression is 7(-4-x)

<h3>By Distributive property a(b+c)=ab+ac</h3>

7(-4-x) =(7)(-4)+(7)(-x)

=-28-7x

Hence the matched equivalent expressions are

1) -7(-4+x) =28-7x

2) -7(4-x) =-28+7x

3) 7(4+x) =28+7x

4) 7(-4-x) =-28-7x

You might be interested in

Susan was posting gifts to her family. She weighed three envelopes before posting them. Geace Envelope A Envelope B Envelope C •

Blababa [14]

Answer:

5x+50

Step-by-step explanation:

you have one x. An x plus fifty. And 3 mire x's. So 5 x's and a 50.

8 0

3 years ago

Fraction - Subtrction : 15 5/11 - 7 3/12

GrogVix [38]

Answer:

$= 8 \frac{27}{132} = 8\frac{9}{44}\\$

Step-by-step explanation:

$15 \frac{5}{11} - 7 \frac{3}{12} \\ \frac{170}{11} - \frac{87}{12} \\ \frac{2040 - 957}{132} \\ = \frac{1083}{132} \\ = 8 \frac{27}{132}$

<em>hope</em><em> </em><em>this</em><em> </em><em>helps</em>

<em>brainliest</em><em> </em><em>appreciated</em>

5 0

3 years ago

Read 2 more answers

The side length, s, of a cube is 3x 2y. If V = s3, what is the volume of the cube? 3x3 18x2y 36xy2 8y3 27x3 54x2y 18xy2 2y3 27x3

uranmaximum [27]

The volume of the cube is 27x³ + 8y³ +54x²y + 36xy².

<h2>Volume of cube </h2>

The volume of a cube is the cube of its side.

$\rm{ Volume\ of\ cube = (side)^3$

<h2>Given to us</h2>

side length, s = (3x+2y)

Volume, V = s³

<h3>Algebraic Identity</h3>

$(a+b)^3= a^3 +b^3 +3a^2b+3ab^2$

<h3>The volume of the cube</h3>

$\begin{aligned}Volume &= s^3\\&= (3x+2y)^3\end{aligned}$

Applying algebraic Identity,

$=(3x+2y)^3\\\\ =(3x)^3+(2y)^3+[3\times (3y)^2 \times2y]+[3 \times 3x \times(2y)^2]\\\\= 27x^3 + 8y^3 +54x^2y +36xy^2$

Hence, the volume of the cube is 27x³ + 8y³ +54x²y + 36xy².

Learn more about Algebraic Identity:

brainly.com/question/662239

5 0

2 years ago

What is the answer?<br><br> Help me please this is due today

k0ka [10]

Answer:

Write the number 12489 in words

4 0

3 years ago

Express cos 5x in terms of sine multiples of x

Nataly_w [17]

<span>cos x = [ e^(ix) - e^(-ix) ] / 2i along with [ A - B ]^5 =

( A^5 - B^5) - 5 AB ( A^3 - B^3) + 10 A²B² (A - B )...A = e^(ix) , B = e^(-ix)

[ cos x ] ^5 = (1/32i) { [ e^(5ix) - e^(-5x) ] - 5 [ ( e^(3ix) - e^(-3ix) ] + 10 [ e^(ix) - e^(-ix) ] }

= ( 1 / 16 ) { cos 5x - 5 cos 3x + 10 cos x }.....much faster</span>

8 0

4 years ago