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malfutka [58]
3 years ago
5

Solve for m . − 5 m = − 35 m =

Mathematics
2 answers:
Jlenok [28]3 years ago
4 0

Answer:

The answer is 7. I did the lesson and 7 was the correct answer

Step-by-step explanation:

dolphi86 [110]3 years ago
3 0

Answer: 7

Step-by-step explanation: -35 / -5 = 7

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What is the slope of the line through (-1,8) and (3,-4)?
laila [671]

Hey there!!

How do we find slopes ?

Slope = \frac{y2-y1}{x2-x1}

We are given with two co-ordinates :

(-1,8) and (3,-4)  

Hence, the slope is :

\frac{-4-8}{3+1}

... \frac{-12}{4} = -3

The slope is -3.

Hope my answer helps!

4 0
3 years ago
What does B equal if the problem is y=5/-9x+B
NikAS [45]

Answer:

y=5/-8x+b

or y-b =5/-8x

or y*(-8x)=5+b

or -8xy-5=b

6 0
3 years ago
Two 5-year girls, Alyse and Jocelyn, have been training to run a 1-mile race. Alyse's 1 mile time A is approximately Normally di
tatyana61 [14]

Answer:

1.7 × 10⁻⁴

Step-by-step explanation:

The question relates to a two sample z-test for the comparison between the means of the two samples  

The null hypothesis is H₀:  μ₁ ≤ μ₂

The alternative hypothesis is Hₐ: μ₁ > μ₂

z=\dfrac{(\bar{x}_1-\bar{x}_2)-(\mu_{1}-\mu _{2} )}{\sqrt{\dfrac{\sigma_{1}^{2} }{n_{1}}-\dfrac{\sigma _{2}^{2}}{n_{2}}}}

Where;

\bar {x}_1 = 13.5

\bar {x}_2 = 12

σ₁ = 2.5

σ₂ = 1.5

We set our α level at 0.05

Therefore, our critical z = ± 1.96

For n₁ = n₂ = 23, we have;

z=\dfrac{(13.5-12)-(0)}{\sqrt{\dfrac{2.5^{2} }{23}-\dfrac{1.5^{2}}{23}}} = 3.5969

We reject the null hypothesis at α = 0.05, as our z-value, 3.5969 is larger than the critical z, 1.96 or mathematically, since 3.5969 > 1.96

Therefore, there is enough statistical evidence to suggest that Alyse time is larger than Jocelyn in a 1 mile race on a randomly select day and the probability that Alyse has a larger time than Jocelyn is 0.99983

Therefore;

The probability that Alyse has a smaller time than Jocelyn is 1 - 0.99983 = 0.00017 = 1.7 × 10⁻⁴.

8 0
3 years ago
Aviah uses the treadmill at Biff's Gym. She sets the speed to a constant 4 miles per hour.
dlinn [17]
The bottom right graph
7 0
3 years ago
Solve the triangle. A = 54°, b = 11, c = 8
Delicious77 [7]
In this problem, you apply principles in trigonometry. Since it is not mentioned, you will not assume that the triangle is a special triangle such as the right triangle. Hence, you cannot use Pythagorean formulas. The only equations you can use is the Law of Sines and Law of Cosines.

For finding side a, you can answer this easily by the Law of Cosines. The equation is

a2=b2 +c2 -2bccosA
a2 = 11^2 + 8^2 -2(11)(8)(cos54)
a2 = 81.55
a = √81.55
a = 9 

Then, we use the Law of Sines to find angles B and C. The formula would be

a/sinA = b/sinB = c/sinC
9/sin54° =  11/sinB
B = 80.4°

9/sin54° = 8/sinC
C = 45.6°

The answer would be: a ≈ 9, C ≈ 45.6, B ≈ 80.4
5 0
3 years ago
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