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LiRa [457]
3 years ago
8

Mr. Nelson lost one of his students' test

Mathematics
1 answer:
amid [387]3 years ago
6 0

Complete question :

Mr. Nelson lost one of his students' test papers. He knows that the other 4 students scored as follows: 60, 62, 56, 57. He also knows that the average score is 59.2. What is the score on the missing paper?

Answer:

61

Step-by-step explanation:

Given the following :

Total number of students = 4 + 1 missing = 5

Score on the four avaliable papers = 60, 62, 56, 57

Average score of the 5 papers = 59.2

Score on missing paper :

Sum of each score / number of papers

Sum of each score = sum of available scores + missing score

Let missing score = m

(60 + 62 + 56 + 57 + m) = 235 + m

Recall:

Average = total sum / number of observations

Hence,

59.2 = (235 + m) / 5

59.2 × 5 = 235 + m

296 = 235 + m

m = 296 - 235

m = 61

Missing score = 61

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olga_2 [115]

Answer:

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Step-by-step explanation:

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From table 1,

For a point (1, 2)

k=\frac{2}{1}=2

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k=\frac{3}{2}=1.5

In both the cases 'k' is not same of constant.

Therefore, table (1) is not proportional.

For table (2),

Line passes through (2, 0).

That means there is a x-intercept → (2, 0)

Therefore, table doesn't represent a proportional relationship.

For table (3),

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Therefore, table doesn't represent a proportional relationship.

For table (4),

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k=\frac{3}{1}=3

k=\frac{6}{2}=3

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6 0
3 years ago
Which one and don’t lie!!
4vir4ik [10]

Answer:

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Step-by-step explanation:

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3 0
3 years ago
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MrRa [10]

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Step-by-step explanation:

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3 years ago
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3 years ago
Please help with at least one question.
Cloud [144]
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[/] [/] [/] [] [] = 3/5

[/] [/] [] [] [] [] [] [] [] 2/9

At the end it should be -5/7, 2/9 , 3/5. This method can go the same for problems like these...Hope it helps!
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