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LiRa [457]
3 years ago
8

Mr. Nelson lost one of his students' test

Mathematics
1 answer:
amid [387]3 years ago
6 0

Complete question :

Mr. Nelson lost one of his students' test papers. He knows that the other 4 students scored as follows: 60, 62, 56, 57. He also knows that the average score is 59.2. What is the score on the missing paper?

Answer:

61

Step-by-step explanation:

Given the following :

Total number of students = 4 + 1 missing = 5

Score on the four avaliable papers = 60, 62, 56, 57

Average score of the 5 papers = 59.2

Score on missing paper :

Sum of each score / number of papers

Sum of each score = sum of available scores + missing score

Let missing score = m

(60 + 62 + 56 + 57 + m) = 235 + m

Recall:

Average = total sum / number of observations

Hence,

59.2 = (235 + m) / 5

59.2 × 5 = 235 + m

296 = 235 + m

m = 296 - 235

m = 61

Missing score = 61

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Irina18 [472]
So,

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The other proportion:
\frac{x}{140}

\frac{2}{5} =  \frac{x}{140}

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Multiply the fraction by the appropriate form of 1
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Cecilia's family travel 2/7 of the distance your uncles house on Saturday. They traveled 4/5 of the remaining distance on Sunday
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3 0
3 years ago
Grades on a standardized test are known to have a mean of 1000 for students in the United States. The test is administered to 45
krok68 [10]

Answer:

a

The 95% confidence interval is 1003  <  \mu

b

Yes there is statistically significant evidence that students in Florida perform differently from other students in the United States

Step-by-step explanation:

From the question we are told that

   The population mean is  \mu =  1000

   The sample size is  n =  453

   The sample mean is  \= x  = 1013

    The standard deviation is s =  108

   

Given that the confidence level is  95% then the level of significance is mathematically represented as

            \alpha  =  100 - 95

=>         \alpha  =  5\%

=>          \alpha  = 0.05

The critical value  for \frac{\alpha }{2} obtained from the normal distribution table is          

          Z_{\frac{\alpha }{2} } =  1.96

Generally the margin of error is mathematically represented as

         E =  Z_{\frac{\alpha }{2} } *  \frac{s}{\sqrt{n} }

=>     E =  1.96 *  \frac{108}{\sqrt{453} }

=>      E = 9.946

Generally the 95% confidence interval is mathematically represented as

           \= x  - E  <  \mu <  \= x + E

=>         1013  - 9.946  <  \mu < 1013  + 9.946

=>         1003  <  \mu

Given that the population mean(1000) is not within the 95% confidence interval for l for the average test score for students in Florida, then it means that there is statistically significant evidence that students in Florida perform differently from other students in the United States

 

4 0
3 years ago
20 - 4 { 20÷ 7 ( 7 - 3 )}​
hodyreva [135]

20 -4 { 20÷ 7 ( 7 - 3 )}

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4 0
3 years ago
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shusha [124]

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