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LiRa [457]
2 years ago
8

Mr. Nelson lost one of his students' test

Mathematics
1 answer:
amid [387]2 years ago
6 0

Complete question :

Mr. Nelson lost one of his students' test papers. He knows that the other 4 students scored as follows: 60, 62, 56, 57. He also knows that the average score is 59.2. What is the score on the missing paper?

Answer:

61

Step-by-step explanation:

Given the following :

Total number of students = 4 + 1 missing = 5

Score on the four avaliable papers = 60, 62, 56, 57

Average score of the 5 papers = 59.2

Score on missing paper :

Sum of each score / number of papers

Sum of each score = sum of available scores + missing score

Let missing score = m

(60 + 62 + 56 + 57 + m) = 235 + m

Recall:

Average = total sum / number of observations

Hence,

59.2 = (235 + m) / 5

59.2 × 5 = 235 + m

296 = 235 + m

m = 296 - 235

m = 61

Missing score = 61

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The machine bottled 8,000 bottles in 4 hours. if the rate of the machine were doubled, how long would it take the machine to bot
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Logic.
4 0
3 years ago
Need help on #6 step by step I'm so confused how this works I always get stuck
inna [77]
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6 0
3 years ago
In a random sample of 400 residents of Boston, 320 residents indicated that they voted for Obama in the last presidential electi
coldgirl [10]

Answer:

C.I =  0.7608   ≤ p ≤   0.8392

Step-by-step explanation:

Given that:

Let consider a  random sample n = 400 candidates where  320 residents indicated that they voted for Obama

probability \hat p = \dfrac{320}{400}

= 0.8

Level of significance ∝ = 100 -95%

= 5%

= 0.05

The objective is to  develop a 95% confidence interval estimate for the proportion of all Boston residents who voted for Obama.

The confidence internal can be computed as:

=\hat p  \pm Z_{\alpha/2} \sqrt{\dfrac{ p(1-p)}{n } }

where;

Z_{0.05/2} = Z_{0.025} = 1.960

SO;

=0.8  \pm 1.960 \sqrt{\dfrac{ 0.8(1-0.8)}{400 } }

=0.8  \pm 1.960 \sqrt{\dfrac{ 0.8(0.2)}{400 } }

=0.8  \pm 1.960 \sqrt{\dfrac{ 0.16}{400 } }

=0.8  \pm 1.960 \sqrt{4 \times 10^{-4}}

=0.8  \pm 1.960 \times 0.02}

=0.8  \pm 0.0392

= 0.8 - 0.0392     OR   0.8 + 0.0392  

= 0.7608    OR    0.8392

Thus; C.I =  0.7608   ≤ p ≤   0.8392

3 0
2 years ago
How many intersections are there of the graphs of the equations below?<br><br> One-halfx + 5y = 6
andre [41]

Answer:

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Step-by-step explanation:

8 0
3 years ago
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