Answer:
Step-by-step explanation:
C
l
2
+
2
K
B
r
→
2
K
C
l
+
B
r
2
Given:
300
g
of
C
l
2
300
g
of
K
B
r
(a) Mass of
C
l
2
= 300g
Molecular mass of
C
l
2
= 2(35.45) = 70.906 g
/
m
o
l
No.of moles of
C
l
2
=
m
a
s
s
/
m
o
l
a
r
m
a
s
s
=
300
/
70.906
=
4.23
moles
Mass of
K
B
r
=
300
g
Molar mass of
K
B
r
=
39
+
79.9
=
118.9
g
/
m
o
l
No.of moles of
K
B
r
=
300
/
118.9
=
2.52
moles
Now,
Consider the equation:
C
l
2
+
2
K
B
r
→
2
K
C
l
+
B
r
2
1
mole of
C
l
2
= 2 moles of
K
C
l
4.23
moles of
C
l
2
= 2x4.23=
8.46
moles
2
moles of
K
B
r
= 2 moles of
K
C
l
2.52
moles of
K
B
r
=
2.52
moles
Now convert moles to mass,
Mass of
K
C
l
produced by
C
l
2
=
8.46
×
70.906
=
599.8
g
Mass of
K
C
l
produced by potassium bromide =
2.52
×
74.5
=
187.74
g
Step-by-step explanation:
Hey, there!!
C = {6,8}
n(C) means cardinality of set.
We define cardinality of set as the no. of elements present in set.
It contains 2 no. of elements.
so, its cardinality is n(C) is 2.
<em><u>Hope</u></em><em><u> </u></em><em><u>it helps</u></em><em><u>.</u></em><em><u>.</u></em><em><u>.</u></em>
Answer:
Step-by-step explanation:
You are given the relation 
This means that
The input values of this relation are 
, so the domain of this relation is 
The output values of this relation are 
, so the range of this relation is
It's A), because if the highest exponential would've been uneven, the graph would go up, then down, but as you can see it kinda resembles a parabola, making it one out of A) and B)
as you can see, the graph crosses the system at (0/0), so it can't be C), due to it's constant at the end, being "+1"
so it's A)
Answer:
1 false
2 true
3 true
4 false
5 true
Step-by-step explanation:
f(a) = (2a - 7 + a^2) and g(a) = (5 – a).
1 false f(a) is a second degree polynomial and g(a) is a first degree polynomial
When added together, they will be a second degree polynomial
2. true When we add and subtract polynomials, we still get a polynomial, so it is closed under addition and subtraction
3. true f(a) + g(a) = (2a - 7 + a^2) + (5 – a)
Combining like terms = a^2 +a -2
4. false f(a) - g(a) = (2a - 7 + a^2) - (5 – a)
Distributing the minus sign (2a - 7 + a^2) - 5 + a
Combining like terms a^2 +3a -12
5. true f(a)* g(a) = (2a - 7 + a^2) (5 – a).
Distribute
(2a - 7 + a^2) (5) – (2a - 7 + a^2) (a)
10a -35a +5a^2 -2a^2 -7a +a^3
Combining like term
-a^3 + 3 a^2 + 17 a - 35
