Question

What is the area of a right triangle with side lengths 7,24, and 25?​

Answer 1

Answer:

Area = 84 square unit

Step-by-step explanation:

Given the triangle is right angle triangle. According to Pythagoras theorem, the largest amount the sides is the hypotenuse. and the others are base and height respectively.

Therefore, hypotenuse = 25, base = 7, height = 24

$Area \ of \ triangle = \frac{1}{2} \times \ base \times height$

                        $= \frac{1}{2} \times 7 \times 24 \\\\= 7 \times 12 \\\\= 84 \ square \ unit$

                     

Answer 2

Answer:

A = 84 units^ 2

Step-by-step explanation:

The longest side length is also the hypotenuse of this right triangle:  25.  Therefore the leg lengths must be 7 and 24.  The legs are perpendicular to one another.  If we let the base be 7 and the height 24, then the area of the triangle is A = (1/2)(base)(height), or

A = (1/2)(7)(24) = 84 units^ 2