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3 years ago

I need a prediction about 3/162 being a terminating or non terminating number could someone help?

Mathematics

1 answer:

3241004551 [841]3 years ago

6 0

Answer:

5+5=10

Step-by-step explanation:

your welcome:)

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9(11-k)=3(3k-9) plz help solve for k

melisa1 [442]

Distribute...
99 - 9k = 9k - 27
Add 27 to both sides
126 - 9k = 9k
Add 9k to both sides
126 = 18k
Divide by 18
k = 126 / 18 = 7

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3 years ago

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What is 19.2x10^8 minutes in hours?

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3.2 $10^{7}$

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Determine the converse of the conditional statement: If the lengths of the sides of a rectangle are 6 inches and 4 inches, the a

nlexa [21]

Answer:

If the area is 24 square inches, the lengths of the sides of a rectangle are 6 inches and 4 inches.

Step-by-step explanation:

If the lengths of the sides of a rectangle are 6 inches and 4 inches, the area is 24 square inches.

converse switches the statements

If the area is 24 square inches, the lengths of the sides of a rectangle are 6 inches and 4 inches.

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3 years ago

Five individuals from an animal population thought to be near extinction in a certain region have been caught, tagged, and relea

Talja [164]

Answer:

a) For this case the random variable X follows a hypergometric distribution.

b) $E(X)= n\frac{M}{N}=10 \frac{5}{25}=2$

$Var(X)=n \frac{M}{N}\frac{N-M}{N}\frac{N-n}{N-1}=10\frac{5}{25}\frac{25-5}{25}\frac{25-10}{25-1}=1$

c) $P(X=0)= \frac{(5C0)(25-5 C 10-0)}{25C10}=\frac{1*184756}{3268760}=0.0565$

d) $P(X=5)= \frac{(5C5)(25-5 C 10-5)}{25C10}=\frac{1*15504}{3268760}=0.00474$

Step-by-step explanation:

The hypergometric distribution is a discrete probability distribution that its useful when we have more than two distinguishable groups in a sample and the probability mass function is given by:

$P(X=k)= \frac{(MCk)(N-M C n-k)}{NCn}$

Where N is the population size, M is the number of success states in the population, n is the number of draws, k is the number of observed successes

The expected value and variance for this distribution are given by:

$E(X)= n\frac{M}{N}$

$Var(X)=n \frac{M}{N}\frac{N-M}{N}\frac{N-n}{N-1}$

a. What is the distribution of X?

For this case the random variable X follows a hypergometric distribution.

b. Compute the values for E(X) and Var(X)

For this case n=10, M=5, N=25, so then we can replace into the formulas like this:

$E(X)= n\frac{M}{N}=10 \frac{5}{25}=2$

$Var(X)=n \frac{M}{N}\frac{N-M}{N}\frac{N-n}{N-1}=10\frac{5}{25}\frac{25-5}{25}\frac{25-10}{25-1}=1$

c. What is the probability that none of the animals in the second sample are tagged?

So for this case we want this probability:

$P(X=0)= \frac{(5C0)(25-5 C 10-0)}{25C10}=\frac{1*184756}{3268760}=0.0565$

d. What is the probability that all of the animals in the second sample are tagged?

So for this case we want this probability:

$P(X=5)= \frac{(5C5)(25-5 C 10-5)}{25C10}=\frac{1*15504}{3268760}=0.00474$

4 0

3 years ago

if tom spins the spinner 80 times work out an estimate for the number of times the spinner will land on 3

kodGreya [7K]

Can you provide imformation on how many different areas that it can land on?

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4 years ago