Answer:
The answer is "Options A, B, and E represent mutually exclusive events".
Step-by-step explanation:
Two occurrences that can happen immediately called mutually incompatible. Let's now glance at our options and figure out where the statements are mutually incompatible events.
In Option A: You could see that landing on an unwanted portion and arriving on 2 are events that are locally incompatible, even as undesirable portion contains 3 and 4, and 2 were shaded.
In Option B: Arriving on a shaded part and falling on 3 are also mutually incompatible because there are 3 on a windows azure.
In Option C: A darkened portion and an increasing amount can land while 2 would be an even number as well as on the shaded portion. That number is very much the same.
In Option D: At the same time as 4 is greater than 3 and it is situated upon an undistressed section, landing and attracting a number larger than 3 can happen.
In Option E: Landing on a shaded part and landing on even a shaded part is an excluding event, since shaders may either be shaded or unlit.
Answer:
Step-by-step explanation:
A.
R(x)=px=x(-45 x+1800)=-45 x²+1800 x
B.
C(x)=7000+100 x
C.
P(x)=R(x)-C(x)=-45 x²+1800 x-(7000+100 x)
or P(x)=-45x²+1800 x-100 x-7000
or P(x)=-45 x²+1700 x-7000
Answer:
4.326 x 10^ 3
Step-by-step explanation:
Correct me if wrong please :)
31 in total and the smaller one has 13. So just subtract 31-13 and it means there are 18 balls in the larger bag
Answer:
5y - 6x = 8 or y = 6x/5 + 8/5
Step-by-step explanation:
let M1= gradient of line AB and M2= gradient of the second line
When two lines are perpendicular, the product of their gradients is -1
i.e, M1M2= -1
M2= -1/M1
A(2,9) and B(8,4)
gradient= (y2-y1)/(x2-x1)
M1= (4-9)/(8-2)
= -5/6
M2= -1÷ -5/6
-1 × -6/5= 6/5
Equation of the line passing through C(-3,-2)
[y-(-2)]/[x-(-3)= 6/5
(y+2)/(x+3)= 6/5
5(y+2)= 6(x+3)
5y+10=6x+18
5y= 6x + 8
y= 6x/5 + 8/5