What is the equation of the line with a slope of -3 and passes through the point (-6,-3)
1 answer:
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Answer:
So the solution set of the equations are {(-1,4)}
or
the solution is x = -1 and y = 4
Step-by-step explanation:
Equations given to us are
y = -3x + 1 ..................(i)
2x + 5y = 18 .................(ii)
To find the value of x and y or the solution set of the system of equations
Now in first equation we see that
y = -3x + 1
Putting this value in equation (ii)
which is
2x + 5y = 18
Putting value of y from (i) in it
2x + 5(-3x + 1) = 18
Opening the bracket and multiplying inside
2x -15x + 5 = 18
-13 x + 5 = 18
Subtracting 5 from both sides of the equation
-13x + 5 - 5 = 18 -5
-13x = 13
Dividing both sides by -13
Cutting out the same values gives us
x = -1
For value of y
putting value of x in equation (i)
which is
y = -3x + 1
Putting the value
y = -3(-1)+1
y=3+1
y=4
So the solution set of the equations are {(-1,4)}
or
the solution is x = -1 and y = 4
Answer:
90°
Step-by-step explanation:
Through point O draw a ray on left side of O which is || to AB & CD and take any point P on it.
Therefore,
∠ABO + ∠BOP = 180° (by interior angle Postulate)
118° + ∠BOP = 180°
∠BOP = 180° - 118°
∠BOP = 62°.... (1)
Since, ∠BOP + ∠POD = ∠BOD
Therefore, 62° + ∠POD = 152°
∠POD = 152° - 62°
∠POD = 90°.....(2)
∠POD + ∠ODC = 180° (by interior angle Postulate)
90° + ∠ODC = 180°
∠ODC = 180° - 90°