Can you rephrase the question please?
Given that out of 30 planted seeds only 9 of the m sprouted, then:
Experimental probability =(number of occurrence of event)/(total number of trials made)
=9/30
=3/10
thus the number of seeds that will sprout given that 20 seeds we planted will be:
3/10×20
=6 seeds
Answer:
f(n) = 6n + 12
Step-by-step explanation:
There is a common difference in consecutive number of seats, that is
42 - 36 = 36 - 30 = 30 - 24 = 24 - 18 = 6
This indicates the sequence is arithmetic with nth term
= a₁ + (n - 1)d
where a₁ is the first term and d the common difference
Here a₁ = 18 and d = 6 , then
f(n) = 18 + 6(n - 1) = 18 + 6n - 6 = 6n + 12
<h2>Given :-</h2>
In □PQRS side PQ∥ side RS. If m∠P = 108degree
and m∠R = 53degree
<h2>To Find :-</h2>
m∠Q and m∠S.
<h2>Solution :-</h2>
According to angle sum property
P∠Q=180−∠P
∠Q=180−108

For angle S
∠S=180−∠R
∠S=180−53


I think its ether 2 5/2 or 2 3/2
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