The given expression 
is true
<h3>Proving trigonometry identity</h3>
Given the expression
Note that:
- cotθ = cosθ/sinθ
- cosecθ = 1/sinθ
Substituting the given parameters into the formula;
Find the LCM of both the numerator and denominator
Divide the result to have:
Learn more on proofs of trigonometry identity here: brainly.com/question/7331447
Answer:
Step-by-step explanation:
Remark
AC and BC are the legs of a triangle. You are told that the right angle is at C. Both these sides have one endpoint C. That means that they are the shorter of the three lines. The first thing we must do is find the Hypotenuse. You need the Hypotenuse to get the sin of one or both of the acute angles.
Hypotenuse
a^2 + b^2 = c^2
a = 7
b = 24
c = ?
c^2 = 7^2 + 24^2
c^2 = 49 + 576
c^2 = 625
sqrt(c^2) = sqrt(625)
c = 25
Find the Largest Angle
The largest angle is going to be opposite the longest leg (not the Hypotenuse although you use the hypotenuse).
Sin(A) = 24/ 25
Sin(A) = 0.96
A = Sin-1(0.96)
A = 73.74
-0.25 or -1/4 is the answer
Answer:
the answer is c!
Step-by-step explanation:
:)
Answer:
Step-by-step explanation:
common ratio=18/-3=-108/18=-6, a=-3
sn=a(r^n-1)(r-1)
sn=-3((-6)^n-1)(-6-1)
sn=-3(-6)^8-1)/(-7)
s8=-3(1679615)/(-7)
s8=719836
