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lesantik [10]
3 years ago
14

Please help me answer #8 ❤️

Mathematics
1 answer:
Nat2105 [25]3 years ago
3 0

Answer:

125

Step-by-step explanation:

Area of trapezoid = \frac{a+b}{2} * h

Bases = 11 and 14

(11+14)=25

25/2=12.5

12.5 x 10 = 125

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A triangle has an area of 157.25 square centimeters and a base of 18.5 centimeters . What is the height?
CaHeK987 [17]

Answer:

h = 17

Step-by-step explanation:

Triangle Area Formula:

A=\frac{1}{2} bh\\\\157.25=\frac{1}{2}(18.5)h\\\\157.25=9.25h\\\\h=17

3 0
3 years ago
Read 2 more answers
Solve t/12=4.<br><br> The solution is t=
lyudmila [28]
T=48

You just need to find out how many times 12 goes into a number, 4 times.

Which is 48 because 12x4 is 48 and you can check your answer by dividing 48/12=4
4 0
3 years ago
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Find the original price of the sale item. Original price: ? Discount: 36% Sale price: $32
Levart [38]

Answer:

The discount percentage was 36%. This means that $32 is 64% of the original cost.

Divide $32 by 64%: (32/.64= 50)

The original cost was $50.

Step-by-step explanation:

7 0
3 years ago
Use the graph that shows the solution to f(x)=g(x) .
n200080 [17]

Answer:

1.  x=3   x=1

2.  x=0

Step-by-step explanation:

We want f(x) to equal g(x)

f(x)=g(x)

1/(x-2) = (x-2)

Using cross products

1 = (x-2) * (x-2)

1 = x^2 -2x-2x+4

Subtract 1 from each side

1-1 = ^2 -2x-2x+4-1

0 = x^2 -4x+3

Factoring

What number multiplies to 3 and adds to -4

-3*-1 = 3

-3+-1 = -4

0= (x-3) (x-1)

Using the zero product property

x-3 =0     x-1=0

x=3   x=1



2.  f(x)=x^2+4x+2

g(x)=(1/2)^ x+1


From the graph,we can see they intersect at x=0

5 0
4 years ago
Find the components of the vertical force Bold Upper FFequals=left angle 0 comma negative 4 right angle0,−4 in the directions pa
Nikolay [14]

Answer:

F_p = < - \sqrt{3} , -3 >\\\\F_o = < \sqrt{3} , -1 >

Step-by-step explanation:

- A plane is oriented in a Cartesian coordinate system such that it makes an angle of ( π / 3 ) with the positive x - axis.

- A force ( F ) is directed along the y-axis as a vector < 0 , - 4 >

- We are to determine the the components of force ( F ) parallel and normal to the defined plane.

- We will denote two unit vectors: ( u_p ) parallel to plane and ( u_o ) orthogonal to the defined plane. We will define the two unit vectors in ( x - y ) plane as follows:

- The unit vector ( u_p ) parallel to the defined plane makes an angle of ( 30° ) with the positive y-axis and an angle of ( π / 3 = 60° ) with the x-axis. We will find the projection of the vector onto the x and y axes as follows:

                         u_o = < cos ( 60° ) , cos ( 30° ) >

                         u_o = < \frac{1}{2} ,  \frac{\sqrt{3} }{2} >

- Similarly, the unit vector ( u_o ) orthogonal to plane makes an angle of ( π / 3 ) with the positive x - axis and angle of ( π / 6 ) with the y-axis in negative direction. We will find the projection of the vector onto the x and y axes as follows:

                        u_p = < cos ( \frac{\pi }{6}  ) , - cos ( \frac{\pi }{3} ) >\\\\u_p = < \frac{\sqrt{3} }{2}  , -\frac{1}{2}  >\\

- To find the projection of force ( F ) along and normal to the plane we will apply the dot product formulation:

- The Force vector parallel to the plane ( F_p ) would be:

                          F_p = u_p(F . u_p)\\\\F_p = < \frac{1}{2} , \frac{\sqrt{3} }{2} > [  < 0 , - 4 > . < \frac{1}{2} , \frac{\sqrt{3} }{2} > ]\\\\F_p = < \frac{1}{2} , \frac{\sqrt{3} }{2} > [ -2\sqrt{3}  ]\\\\F_p = < -\sqrt{3}  , -3 >\\

- Similarly, to find the projection of force ( F_o ) normal to the plane we again employ the dot product formulation with normal unit vector (  u_o  ) as follows:

                         F_o = u_o ( F . u_o )\\\\F_o = < \frac{\sqrt{3} }{2} , - \frac{1}{2} > [ < 0 , - 4 > . < \frac{\sqrt{3} }{2} , - \frac{1}{2} > ] \\\\F_o = < \frac{\sqrt{3} }{2} , - \frac{1}{2} > [ 2 ] \\\\F_o = < \sqrt{3} , - 1 >

- To prove that the projected forces ( F_o ) and ( F_p ) are correct we will apply the vector summation of the two orthogonal vector which must equal to the original vector < 0 , - 4 >

                       F = F_o + F_p\\\\< 0 , - 4 > = < \sqrt{3}, -1 > + < -\sqrt{3}, -3 >  \\\\< 0 , - 4 > = < \sqrt{3} - \sqrt{3} , -1 - 3 > \\\\< 0 , - 4 > = < 0 , - 4 >  .. proven                    

8 0
4 years ago
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