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Drupady [299]
3 years ago
13

Solve the equation with special factors. (Please show all steps) 4p^4 - 25p^2 = -16p^2

Mathematics
2 answers:
daser333 [38]3 years ago
7 0

Answer:

The solutions can be p=3/2 or p=-3/2

Step-by-step explanation:

4p^4 - 25p^2 + 16p^2 = 0

4p^4 - 9p^2 = 0

4p^2 - 9p = 0

p^2 = 9/4

p = sqrt(9/4)

p = 3/2 or p = -3/2

Nataly [62]3 years ago
6 0

Answer:

p = 0 , p = ± \frac{3}{2}

Step-by-step explanation:

4p^{4} - 25p² = - 16p² ( add 16p² to both sides )

4p^{4} - 9p² = 0 ← factor out p² from both sides

p²(4p² - 9) = 0 ←  factor is a difference of squares

p²(2p - 3)(2p + 3) = 0

Equate each factor to zero and solve for p

p² = 0

p = 0 ( multiplicity of 2 )

2p - 3 = 0 ⇒ 2p = 3 ⇒ p = \frac{3}{2}

2p + 3 = 0 ⇒ 2p⇒ = - 3 ⇒ p = - \frac{3}{2}

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Using the z-distribution, it is found that the needed sample sizes are:

a) 242

b) 1842

In a sample with a number n of people surveyed with a probability of a success of \pi, and a confidence level of \alpha, we have the following confidence interval of proportions.

\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}

In which z is the z-score that has a p-value of \frac{1+\alpha}{2}.

The margin of error is:

M = z\sqrt{\frac{\pi(1-\pi)}{n}}

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Item a:

The estimate is:

\pi = 0.223 - 0.189 = 0.034

The sample size is <u>n for which M = 0.03</u>, then:

M = z\sqrt{\frac{\pi(1-\pi)}{n}}

0.03 = 2.575\sqrt{\frac{0.034(0.966)}{n}}

0.03\sqrt{n} = 2.575\sqrt{0.034(0.966)}

\sqrt{n} = \frac{2.575\sqrt{0.034(0.966)}}{0.03}

(\sqrt{n})^2 = \left(\frac{2.575\sqrt{0.034(0.966)}}{0.03}\right)^2

n = 241.97

Rounding up, a sample of 242 is needed.

Item b:

No prior estimates, hence \pi = 0.5 is used.

M = z\sqrt{\frac{\pi(1-\pi)}{n}}

0.03 = 2.575\sqrt{\frac{0.5(0.5)}{n}}

0.03\sqrt{n} = 2.575\sqrt{0.5(0.5)}

\sqrt{n} = \frac{2.575\sqrt{0.5(0.5)}}{0.03}

(\sqrt{n})^2 = \left(\frac{2.575\sqrt{0.5(0.5)}}{0.03}\right)^2

n = 1841.8

Rounding up, a sample of 1842 is needed.

For more on the z-distribution, you can check brainly.com/question/25404151

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