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Llana [10]
3 years ago
9

Find P(C|Y) from the information in the table. To the nearest tenth, P(C|Y) =

Mathematics
2 answers:
Arte-miy333 [17]3 years ago
5 0
The answer is .5 just took the test
Likurg_2 [28]3 years ago
4 0
P(CIY)=[P((C and Y)]/P(Y)
P(C)=40/146=20/73
P(Y)=30/146=15/73
Thus:
P(C and Y)=15/146=
Hence:
P(CIY)=(15/146)/(15/73)=1/2
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How can I solve this question???
eduard

Answer:

144°

Step-by-step explanation:

step 1

Find the measure of the central angle of the regular pentagon

Divide 360 degrees by 5 (the number of sides)

360\°/5=72\°

Let

c----> the center of the pentagon

we know that

m∠ECA=72°

m∠ACB=72°

therefore

m∠ECB=m∠ECA+m∠ACB

substitute the values

m∠ECB=72°+72°=144°

The measure of angle ECB is equal to the degrees that the pentagon rotate

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3 years ago
A triangle's side lengths are 15 cm and 10 cm. Write an inequality to determinte the possible measure for the missing side lengt
Klio2033 [76]

Answer:

the missing side lenght = x

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0 < x < 25 cm

7 0
3 years ago
Blanca runs 8 laps around the track each day to train for an endurance race. She times each lap to practice her pacing for the r
Artist 52 [7]

Answer:

A graph shows lap time (seconds) labeled 82 to 98 on the horizontal axis and the number of laps on the vertical axis. 1 lap was 82 to 84 seconds.  4 laps were 84 to 86 seconds. 2 laps were 86 to 88 seconds. 4 laps were 88 to 90 seconds. 6 laps were 90 to 92 seconds. 5 laps were 92 to 94 seconds. 2 laps were 94 to 96 seconds. 0 laps were 96 to 98 seconds

Step-by-step explanation:

The given table is presented as follows;

\begin{array}{ccc}Day \ 1 \ lap \ times \ (seconds)&Day \ 2 \ lap \ times \ (seconds)&Day \ 3 \ lap \ times \ (seconds)\\83&87&85\\92&90&86\\91&92&91\\89&91&93\\94&92&91\\93&95&89\\88&90&88\\84&85&84\end{array}The number of laps in the range 82 to 84 seconds = 1

The number of laps in the range 84 to 86 seconds = 4

The number of laps in the range 86 to 88 seconds = 2

The number of laps in the range 88 to 90 seconds = 4

The number of laps in the range 90 to 92 seconds = 6

The number of laps in the range 92 to 94 seconds = 5

The number of laps in the range 94 to 96 seconds = 2

The number of laps in the range 96 to 98 seconds = 0

Therefore, the histogram that represents Blanca's lap times for the three days of practice is described as follows;

A graph shows lap time (seconds) labeled 82 to 98 on the horizontal axis and the number of laps on the vertical axis. 1 lap was 82 to 84 seconds.  4 laps were 84 to 86 seconds. 2 laps were 86 to 88 seconds. 4 laps were 88 to 90 seconds. 6 laps were 90 to 92 seconds. 5 laps were 92 to 94 seconds. 2 laps were 94 to 96 seconds. 0 laps were 96 to 98 seconds

5 0
3 years ago
Solve the triangle for all missing sides, rounded to the nearest tenth, and angles, rounded to the nearest degree.
evablogger [386]

Answer:

x=32 y=416 M<ABC=158°

Step-by-step explanation:

6 0
3 years ago
Help me pwes I need it.
MA_775_DIABLO [31]

Answer:

1/10

when you do the LCM you get 70

divide each fraction by 70 and you will get the least to be a tenth

6 0
3 years ago
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