Read the word problem.
2 answers:
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Example Question:
X²+6x-14=0
Quadratic equations are usually in the form Ax²+Bx=C. Completing the Square is a technique for rewriting this equation in the form (x+a²)+b.
The example I provided is in standard form.
Here's what I did:
Step 1: Move the "C" to the other side (in this case it's negative 14, so you add 14 to both sides of the equation to move it).
Step 2: Leave a blank after Ax²+Bx. In this case, it'll look like: X²+6x+_____= 14.
Step 3: Use the box to find the missing "C". Idk if you can see the photo after the 1st one, but I circled the spaces in green. Those spaces indicate 2 factors that add up for B (in this case, 6). Those same factors will eventually multiply each other to get 9.
Step 4: Give the new "C" to both sides of the equation. What this means is that after you multiply the factors on the outside of the box, you put the number on both sides. The 3rd picture I drew is the process of finding the outer factors (by plugging in 3x to the spaces that were circled).
If you can't see it, it's (X+3)•(X+3).
The 4th picture is me plugging the new "C" (9) to both sides of the equation. 3 times 3 is 9. You multiply the 3's on the outside to get the factors on the inside.
Step 5: Use Step 3 box to write (perfect square)² of left hand side.
What this means is that you take the factors on the outside and rewrite it in perfect square form. like shown in picture 5. If you can't see it, it's like this:
(X+3)•(X+3) turns to (X+3)²=23.
The 23 was from adding 14+9 together.
So the final Answer would be:
(X+3)²=23.
If you check the picture below
the rectangular solid is a 6x6x6, so all sides are equal thus is a cube
is painted on all faces, so the only part that's painted is the faces, ok
then you split it like in the picture, you have all 6 faces painted there,
now, let's say each of those 6 faces are cut in 2cm
how many of those 2cm pieces will each have? so get that amount for each and sum them up, that's how many of the cubes have one face painted
only the cubes that are part of the face, which was painted, are the ones that have a painted face themselves
keep in mind that each face is a 6x6 rectangle
notice the 2nd picture below
the rectangular solid is a 6x6x6, so all sides are equal thus is a cube
is painted on all faces, so the only part that's painted is the faces, ok
then you split it like in the picture, you have all 6 faces painted there,
now, let's say each of those 6 faces are cut in 2cm
how many of those 2cm pieces will each have? so get that amount for each and sum them up, that's how many of the cubes have one face painted
only the cubes that are part of the face, which was painted, are the ones that have a painted face themselves
keep in mind that each face is a 6x6 rectangle
notice the 2nd picture below