PUT THESE NUMBERS FROM LEAST TO GREATEST
2 answers:
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Part A.
We could take, for example:
For x ≥ -3 we have vertical line (x-intercept = -3) and shaded region on the right side of the line.
For y ≥ 3 we have horizontal line (y-intercept = 3) and shaded region above that line.
Part B.
Simply, substitute x and y coordinates of D and E <span>to the system of inequalities from part A, and check if its is true, what we get.
</span>
so point D is a solution,
and point E is also a solution to <span>our system of inequalities.
</span>
Part C.
There are two ways we could do that. First is the same as in part B. We substitute x and y coordinates of each school and check if inequality is true or false:
So Timothy can attend schools C and F.
We can also draw a graph of that inequality (pic 2).
We could take, for example:
For x ≥ -3 we have vertical line (x-intercept = -3) and shaded region on the right side of the line.
For y ≥ 3 we have horizontal line (y-intercept = 3) and shaded region above that line.
Part B.
Simply, substitute x and y coordinates of D and E <span>to the system of inequalities from part A, and check if its is true, what we get.
</span>
so point D is a solution,
and point E is also a solution to <span>our system of inequalities.
</span>
Part C.
There are two ways we could do that. First is the same as in part B. We substitute x and y coordinates of each school and check if inequality is true or false:
So Timothy can attend schools C and F.
We can also draw a graph of that inequality (pic 2).