We have the frequencies for each of the grades. We can estimate the number of students graded by adding all those frequencies. Let's call N the total number of grades:

$\begin{gathered} N=4+10+17+6+2 \\ N=39 \end{gathered}$

We have then a total number of grades of 39.

The corresponding relative frequency for a grade is the ratio of the frequency to the total number of "samples", 39 in this case.

Then, for grade A, the relative frequency (RF) will be:

$RF_A=\frac{4}{39}\approx0.10256\approx10.26\text{ \%}$

This will be the fraction of the total grades that are A. Represented as a percentage will be 10.26%, rounded to two decimal places.

Now, to complete the table we do the same for the other frequencies:

For grade B:

$RF_B=\frac{10}{39}\approx0.2564\approx25.64\text{ \%}$

For grade C:

$RF_C=\frac{17}{39}\approx0.4359\approx43.59\text{ \%}$

For grade D:

$RF_D=\frac{6}{39}\approx0.1538\approx15.38\text{ \%}$

For grade F:

$RF_D=\frac{2}{39}\approx0.0513\approx5.13\text{ \%}$

4 0

1 year ago

How can you add eight 8's to get the number 1,000? (only use addition)

Fudgin [204]

The answer is 888+88+8+8+8

6 0

3 years ago

Serena has a summer job as a lifeguard at the neighborhood pool. She earns $240 a week. By rounding her weekly income to the nea

Nesterboy [21]

<h2>Answer: B </h2>

Step-by-step explanation:

If your rounding her weekly income you would go down to $200 then take that times 11 for each week, giving you $2,200 roughly

3 0

3 years ago