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2 years ago

Does a ti 83 plus calculator work the same as a ti 84?

2 answers:

7 0

Yes. The two calculators are the same more or less overall. They have the same functions and features. There are slight differences (eg: the TI84 is slightly faster than the 83 version), but it's not too big a deal since you can do the same math with both versions.

If you can, I recommend using online tools such as Desmos or GeoGebra. These tools are much faster compared to the TI83 and TI84. Also, they allow for multiple colors to be used, so you can tell the graphs apart. There are lots of other features as well (way too many to go over right now), and the best part is that both tools Desmos and GeoGebra are free. Unfortunately, your teacher may not allow you to use them in a test setting. However, I would ask and they may allow a limited version to be used in some capacity.

Roman55 [17]2 years ago

5 0

Answer:

Yes. Both are graphing calculators. TI 83 has a black only screen while the TI 84 has a colored screen

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4,0000000000×10,00000000

Mademuasel [1]

Answer:

yes 40

Step-by-step explanation:

she got it correct

4 0

2 years ago

How do I solve this?

Korvikt [17]

The interior angles of any triangle always sum to 180°.

In the triangle, angles C and D are labeled congruent, so the missing angle has measure

180° - 2 (6x - 5)°

This angle is supplementary to the one labeled (11x + 1)°, which means

180° = (11x + 1)° + (180° - 2 (6x - 5)°)

Solve for x :

180° = (11x + 1)° + 180° - 2 (6x - 5)°

0 = (11x + 1)° - 2 (6x - 5)°

0 = (11x)° + 1° - (12x)° + 10°

(12x - 11x)° = 1° + 10°

x° = 11°

x = 11

5 0

2 years ago

Jose makes $8 an hour plus an

Anna71 [15]

528= 8x+240
288=8x
x=36 hours

7 0

2 years ago

Read 2 more answers

Hello everyone, could you please solve this problem step by step. I don't have the exact solution and there are no options for i

lara31 [8.8K]

Answer:

The area of the shaded part = 61.46

Step-by-step explanation:

Assume the hypotenuse of the triangle is c (c>0)

As the triangle inscribed in the semi circle is the right angle triangle, its hypotenuse is equal to the diameter of the circle.

The hypotenuse of the triangle can be calculated by Pythagoras theorem as following: $c^{2} =a^{2} +b^{2} =(2\sqrt{5}) ^{2} + (4\sqrt{5}) ^{2} = 20 + 80 = 100$

=> c = 10

So that the semi circle has the diameter = 10 => its radius = 5

The total area of 2 semi circles is equal to the area of the circle with radius =5

=> The total area of 2 semi circles is: $\pi$ x $5^{2}$ = 25 $\pi$

The area of a triangle inscribed in the semi circle is: 1/2 x a x b = 1/2 x $2\sqrt{5\\$ x $4\sqrt{5}$ = 20

=> The area of 2 triangles inscribed in 2 semi circles is: 2 x 20 = 40

The area of the square is: $c^{2}$ = $10^{2} =100$

It can be seen that:

The area of the shaded part = The area of the square - The total area of 2 semi circles + The total are of 2 triangles inscribed in semi circles

= 100 - 25 $\pi$ + 40 = 61.46

6 0

2 years ago

Use a system of equations to solve this problem.

Grace [21]

X = amount of seeds.

y = amount of dried fruits.

we know the snack mix contains both, and we know is 10oz, thus x + y = 10, whatever ounces "x" and "y" are.

how much is it for "x" ounces if each one costs $1.5? well is just 1.5*x or 1.5x.

how much is it for "y" ounces if each one costs $2.5? well is just 2.5*x or 2.5x.

the mix contains 10 ounces, each of which costs $2.2 each, how much will it be then for 10 oz? well, is just 10 * 2.2, or $22.

since the whole 10 oz snack mix costs 22 bucks, then 1.5x + 2.5y = 22.

$\bf \begin{cases}
x+y=10\implies \boxed{y}=10-x\\
1.5x+2.5y=22\\
-------------\\
1.5x+2.5\left( \boxed{10-x} \right)=22
\end{cases}
\\\\\\
1.5x+25-2.5x=22\implies -x+25=22\implies 3=x$

how many ounces of dried fruit is there anyway? well, y = 10 - x.

4 0

3 years ago