The for this problem would be C, 50
The first step to solving this expression is to factor out the perfect cube
![\sqrt[3]{m^{2} n^{3} X n^{2} }](https://tex.z-dn.net/?f=%20%5Csqrt%5B3%5D%7Bm%5E%7B2%7D%20%20n%5E%7B3%7D%20X%20n%5E%7B2%7D%20%20%20%7D%20)
The root of a product is equal to the product of the roots of each factor. This will make the expression look like the following:
![\sqrt[3]{ m^{2} n^{2} }](https://tex.z-dn.net/?f=%20%5Csqrt%5B3%5D%7B%20m%5E%7B2%7D%20n%5E%7B2%7D%20%20%7D%20)
Finally,, reduce the index of the radical and exponent with 3
n
![\sqrt[3]{ m^{2} n^{2} }](https://tex.z-dn.net/?f=%20%5Csqrt%5B3%5D%7B%20m%5E%7B2%7D%20n%5E%7B2%7D%20%20%7D%20)
This means that the correct answer to your question is n
![\sqrt[3]{ m^{2} n^{2} }](https://tex.z-dn.net/?f=%20%5Csqrt%5B3%5D%7B%20m%5E%7B2%7D%20n%5E%7B2%7D%20%7D%20)
.
Let me know if you have any further questions
:)
Answer:
(3)(c) + 43 ≥ 100
Step-by-step explanation:
Given:
Total number of friends = 3 friends
Number of card already have = 43
Total number of card at least want to collect = 100
Find:
Inequality
Computation:
Assume;
Same number of card each friend collect = c
Total number of card at least want to collect ≤ (Total number of friends)(Same number of card each friend collect) + Number of card already have
Total number of card at least want to collect ≤ (3)(c) + 43
100 ≤ (3)(c) + 43
(3)(c) + 43 ≥ 100
First find the common denominator
5/8=25/40
2/5=16/40
3/4=30/40
Next you can cross multiply
25/40=x/10 pounds
16/40=x/10 pounds
30/40=x/10 pounds
First
25(10)/40= 6.25 pounds
16(10)/40= 4pounds
30(10)/40= 7.5 pounds
These are the amounts that were left in the bag
10-6.25=3.75
10-4=6
10-7.5=2.5
3.75+6+2.5= 12.25
All together they put 12.25 pounds of soil in the flower bed