There were 16 stairs.carlos walked halfway up.how many steps did he climb

Please help it’s due tonight. Your help will be greatly appreciated.There is also a graph. WILL PUT YOU AS BRAINLY!!!!!!

chubhunter [2.5K]

Answer: see below

Step-by-step explanation:

The shape is a trapezoid

Base 1 (BH) is 10

Base 2 (QA) is 14

Height is 5

Area

$A=\frac{base_{1} +base_{2} }{2} h$

$A=\frac{10+14}{2} *5\\A=12*5\\A=60$

Find distance between QB and HA

$D=\sqrt{(x_{2} -x_{1}) ^{2}+(y_{2}-y_{1}) ^{2}$

Q( -4,4) B (-2,9)

$D=\sqrt{(-2--4)^{2}+(9-4)^{2} } \\D=\sqrt{2^{2} +5^{2} } \\D=\sqrt{29}$

Perimeter

$P=10+14+2\sqrt{29} \\P=24 +2\sqrt{29} \\P= 24+10.77\\P=34.77$

5 0

3 years ago

The least total cost method (LTC) lot-sizing technique calculates the order quantity by comparing the carrying cost and the setu

rewona [7]

Answer:

True

Step-by-step explanation:

The least total cost method is the method in which the total cost of the ordering cost and the total carrying cost is equal among various lot size available.

The order quantity should be choose when the total ordering cost and the total carrying cost equal to each other

The formula to compute the economic order quantity is shown below:

a. The computation of the economic order quantity is shown below:

$= \sqrt{\frac{2\times \text{Annual demand}\times \text{Ordering cost}}{\text{Carrying cost}}}$

It is always be expressed in units

The formula to compute the ordering cost is

$= \frac{Annual\ demand}{Economic\ order\ quantity}\times ordering\ cost\ per\ order$

And, the formula to compute the carrying cost is

$= \frac{Economic\ order\ quanity}{2}\times carrying\ cost\ per\ unit$

Hence, the given statement is true

8 0

3 years ago

The vertices of triangle RST are R (-7, 5), S(17, 5), T(5, 0). What is the perimeter of triangle RST?

MaRussiya [10]

$~\hfill \stackrel{\textit{\large distance between 2 points}}{d = \sqrt{( x_2- x_1)^2 + ( y_2- y_1)^2}}~\hfill~ \\\\[-0.35em] ~\dotfill\\\\ R(\stackrel{x_1}{-7}~,~\stackrel{y_1}{5})\qquad S(\stackrel{x_2}{17}~,~\stackrel{y_2}{5}) ~\hfill RS=\sqrt{(~~ 17- (-7)~~)^2 + (~~ 5- 5~~)^2} \\\\\\ ~\hfill RS=\sqrt{( 24)^2 + ( 0)^2}\implies \boxed{RS=24} \\\\\\ S(\stackrel{x_1}{17}~,~\stackrel{y_1}{5})\qquad T(\stackrel{x_2}{5}~,~\stackrel{y_2}{0}) ~\hfill ST=\sqrt{(~~ 5- 17~~)^2 + (~~ 0- 5~~)^2}$

$~\hfill ST=\sqrt{( -12)^2 + ( -5)^2}\implies \boxed{ST=13} \\\\\\ T(\stackrel{x_1}{5}~,~\stackrel{y_1}{0})\qquad R(\stackrel{x_2}{-7}~,~\stackrel{y_2}{5}) ~\hfill TR=\sqrt{(~~ -7- 5~~)^2 + (~~ 5- 0~~)^2} \\\\\\ ~\hfill TR=\sqrt{( -12)^2 + (5)^2}\implies \boxed{TR=13} \\\\[-0.35em] ~\dotfill\\\\ ~\hfill \stackrel{\textit{\LARGE perimeter}}{24~~ + ~~13~~ + ~~13\implies \text{\LARGE 50}}~\hfill$

3 0

1 year ago

Save Work out the size of angle AED.<br> b) Work out x

Mamont248 [21]

Answer:

x = 10°

Step-by-step explanation:

a). Since, opposite angles of a cyclic quadrilateral are supplementary angles"

Therefore, in cyclic quadrilateral ABDE,

m∠ABD + m∠AED = 180°

110° + m∠AED = 180°

m∠AED = 180° - 110°

= 70°

b). AD = ED [Given]

m∠EAD = m∠AED [Since, opposite angles of equal sides are equal in measure]

m∠EAD = m∠AED = 70°

By triangle sum theorem in ΔABD,

m∠BAD + m∠ABD + m∠ADB = 180°

m∠BAD + 110° + 40° = 180°

m∠BAD = 180 - 150

= 30°

m∠AEB = m∠AED + m∠DAB [By angles addition postulate]

m∠AEB = 70° + 30°

= 100°

By triangle sum theorem in the large triangle,

x° + m∠AEB + m∠EAB = 180°

x° + 100° + 70° = 180°

x = 180 - 170

x = 10°

8 0

2 years ago

How much of the circle is shaded 1/4+3/7

Snezhnost [94]

I hope this helps you

1/4+3/7

7/7.4+3.4/7.4

7/28+12/28

19/28

4 0

3 years ago