X = 2
y = -9
16 - negative 18 = -2
1. y - y₁ = m(x - x₁)
y - (-7) = 6(x - (-8))
y + 7 = 6(x + 8)
y + 7 = 6(x) + 6(8)
y + 7 = 6x + 48
<u> - 7 - 7</u>
y = 6x + 41
2. <u>y₂ - y₁</u> = <u>-8 - (-3)</u> = <u>-8</u><u> + 3</u> = <u>-5</u> = -1²/₃
x₂ - x₁ -1 - (-4) -1 + 4 3
3. 2x - 3y = 11
<u>3x + 3y = 9</u>
<u>5x</u> = <u>20</u>
5 5
x = 4
2x - 3y = 11
2(4) - 3y = 11
8 - 3y = 11
<u>- 8 - 8</u>
<u>-3y</u> = <u>3</u>
-3 -3
y = -1
(x, y) = (4, -1)
4. 2x - 5y = -7 ⇒ -6x + 15y = 21
5x - 3y = 11 ⇒ <u>-25x + 15y = -55</u>
<u>19x</u> = <u>76</u>
19 19
x = 4
2x - 5y = -7
2(4) - 5y = -7
8 - 5y = -7
<u>- 8 - 8</u>
<u>-5y</u> = <u>-15</u>
-5 -5
y = 3
(x, y) = (4, 3)
5. 4.9 × 10¹¹, 8.9 × 10¹⁸, 1.3 × 10⁸, 6.7 × 10⁸, 2.7 × 10⁸
<u>1.3 × 10³</u>, 2.7 × 10⁸, 6.7 × 10⁸, 4.9 × 10¹¹, <u>8.9 × 10¹⁸</u>
Least Greatest
<span>Which expression can be used to determine the side length of the rhombus?
The answer is the first option: 10/Cos(30°) Explanation:
1. As you can see in the figure attached, there is a right triangle and its hypotenuse (which is represented with the letter "x") is the side you want to calculate. So, you have:
Cos(</span>α)=Adjacent leg/Hypotenuse
<span>
</span>α=30°
<span> Adjacent leg=(20 in)/2=10 in
Hypotenuse=x
2. When you substitute these values into the formula, you obtain:
</span>
Cos(α)=Adjacent leg/Hypotenuse
<span> Cos(30°)=10/x
3. Therefore, you obtain the expression to determine the side length of the rhombus by clearing the hypotenuse "x", as below:
x=10/Cos(30°)
</span>
Answer:
1. C
2. A
Step-by-step explanation:
I hope this helps!