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matrenka [14]
3 years ago
6

a cow is tied to a pole fixed at the mid-point of a side of a square field of side 40m by means of a 14m long rope find the area

that cow can graze pls explain​
Mathematics
1 answer:
svp [43]3 years ago
4 0

Step-by-step explanation:

The area that cow can graze is in the form of semicircle.

Radius of semicircle

Length of rope =14 m

Required area = 1/2 ×πr

=1/2×22/7×r^2

=1/2×22/7×14×14

=308m2

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zmey [24]
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Equation of the line contains the points (-3,2) and (5,-5)
makkiz [27]

For this case we have that by definition, the equation of the line of the slope-intersection form is given by:

y = mx + b

Where:

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b: It is the cut-off point with the y axis

We have the following points through which the line passes:

(x_ {1}, y_ {1}): (- 3,2)\\(x_ {2}, y_ {2}) :( 5, -5)

So the slope is:

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Thus, the equation of the line is of the form:

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We substitute one of the points and find "b":

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y = - \frac {7} {8} x- \frac {5} {8}

Answer:

y = - \frac {7} {8} x- \frac {5} {8}

6 0
3 years ago
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kifflom [539]
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5 0
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klasskru [66]

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<h2>Answer:</h2>

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5 0
3 years ago
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