Answer:
81.85%
Step-by-step explanation:
Given :
The average summer temperature in Anchorage is 69°F.
The daily temperature is normally distributed with a standard deviation of 7°F .
To Find:What percentage of the time would the temperature be between 55°F and 76°F?
Solution:
Mean = 
Standard deviation = 
Formula : 
Now At x = 55


At x = 76


Now to find P(55<z<76)
P(2<z<-1)=P(z<2)-P(z>-1)
Using z table :
P(2<z<-1)=P(z<2)-P(z>-1)=0.9772-0.1587=0.8185
Now percentage of the time would the temperature be between 55°F and 76°F = 
Hence If the daily temperature is normally distributed with a standard deviation of 7°F, 81.85% of the time would the temperature be between 55°F and 76°F.
Answer:
The estimate is 
Step-by-step explanation:
From the question we are told that
The sample size is n = 522
The sample proportion of students would like to talk about school is 
Given that the confidence level is 90 % then the level of significance can be mathematically evaluated as



Next we obtain the critical value of
from the normal distribution table, the value is

Generally the margin of error can be mathematically represented as

=> 
=> 
Generally the estimate the proportion of all teenagers who want more family discussions about school at 90% confidence level is

substituting values

<span>the answer will have to be the second choice cause it seems more correct</span>
-4x + 6y = 12
x + 2y = -10
First solve for x in the second equation
x + 2y = -10
x = -10 - 2y
Now we have a value for x so we can substitute it into the other equation
-4 (-10 - 2y) + 6y = 12
Now solve for y
40 + 8y + 6y = 12
40 + 14y = 12
14y = -28
y = -2
Now we have a value for y that we can plug into one of the original equations so we can solve for x
x + 2y = -10
x + 2(-2) = -10
x - 4 = -10
x = -6
Your solution set is
(-6, -2)
Answer:
2,750 milliliters into gallons=0.72647314
Step-by-step explanation: