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matrenka [14]
3 years ago
6

a cow is tied to a pole fixed at the mid-point of a side of a square field of side 40m by means of a 14m long rope find the area

that cow can graze pls explain​
Mathematics
1 answer:
svp [43]3 years ago
4 0

Step-by-step explanation:

The area that cow can graze is in the form of semicircle.

Radius of semicircle

Length of rope =14 m

Required area = 1/2 ×πr

=1/2×22/7×r^2

=1/2×22/7×14×14

=308m2

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The average summer temperature in Anchorage is 69°F. If the daily temperature is normally distributed with a standard deviation
mafiozo [28]

Answer:

81.85%

Step-by-step explanation:

Given :

The average summer temperature in Anchorage is 69°F.

The daily temperature is normally distributed with a standard deviation of 7°F .

To Find:What percentage of the time would the temperature be between 55°F and 76°F?

Solution:

Mean = \mu = 69

Standard deviation = \sigma = 7

Formula : z=\frac{x-\mu}{\sigma}

Now At x = 55

z=\frac{55-69}{7}

z=-2

At x = 76

z=\frac{76-69}{7}

z=1

Now to find P(55<z<76)

P(2<z<-1)=P(z<2)-P(z>-1)

Using z table :

P(2<z<-1)=P(z<2)-P(z>-1)=0.9772-0.1587=0.8185

Now percentage of the time would the temperature be between 55°F and 76°F = 0.8185 \times 100 = 81.85\%

Hence If the daily temperature is normally distributed with a standard deviation of 7°F, 81.85% of the time would the temperature be between 55°F and 76°F.

7 0
3 years ago
An Article a Florida newspaper reported on the topics that teenagers most want to discuss with their parents. The findings, the
Sergio039 [100]

Answer:

The estimate is  P__{hat}} \pm E  = 0.37 \pm 0.0348

Step-by-step explanation:

From the question we are told that  

    The sample size is  n =  522

    The sample proportion of students  would like to talk about school is  \r p__{hat}} =  0.37

  Given that the confidence level is  90 % then the level of significance can be mathematically evaluated as

                  \alpha  =  100 - 90

                  \alpha  =  10\%

                  \alpha  =  0.10

Next we obtain the critical value of  \frac{\alpha }{2} from the normal distribution table, the value is  

               Z_{\frac{\alpha }{2} } =Z_{\frac{0.10}{2} } =  1.645

Generally the margin of error can be mathematically represented as

               E =  Z_{\frac{\alpha }{2} } *  \sqrt{\frac{\r P_{hat}(1- \r P_{hat} )}{n } }

=>            E = 1.645 *  \sqrt{\frac{0.37 (1- 0.37  )}{522 } }

=>             E = 0.0348

Generally the estimate the proportion of all teenagers who want more family discussions about school at 90% confidence level is  

                       P__{hat}} \pm  E

substituting values

                     0.37 \pm 0.0348

5 0
3 years ago
Please help me I only have one more question, Thank you! - Alyssa
lesya692 [45]
<span>the answer will have to be the second choice cause it seems more correct</span>
7 0
3 years ago
HEY GUYS PLEASE HELP ME ANYONE I MEAN ANYONE WHOO EXPLAINS WELL AND NOT FOR THE POINTS WILL BE MARKED AS BRAINLIEST .SOLVE EACH
cupoosta [38]
-4x + 6y = 12
x + 2y = -10

First solve for x in the second equation

x + 2y = -10
x = -10 - 2y

Now we have a value for x so we can substitute it into the other equation

-4 (-10 - 2y) + 6y = 12

Now solve for y

40 + 8y + 6y = 12
40 + 14y = 12
14y = -28
y = -2

Now we have a value for y that we can plug into one of the original equations so we can solve for x

x + 2y = -10
x + 2(-2) = -10
x - 4 = -10
x = -6

Your solution set is

(-6, -2)
5 0
3 years ago
2,750 milliliters into gallons.
yan [13]

Answer:

2,750 milliliters into gallons=0.72647314

Step-by-step explanation:

4 0
2 years ago
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