Answer:
h=5/2
Step-by-step explanation:
59 is an outlier it's not in the 70s
Answer:
The slope is the rise over run, so...
It is 3/1 or just 3.
Step-by-step explanation:
Rise/run is slope
(2,1) is a point on the line, and so is (3,4)
Answer:
![P(X\leq 1) = 0.331](https://tex.z-dn.net/?f=P%28X%5Cleq%201%29%20%3D%200.331)
Step-by-step explanation:
Given
Poisson Distribution;
Average rent in a week = 2.3
Required
Determine the probability of renting no more than 1 apartment
A Poisson distribution is given as;
![P(X = x) = \frac{y^xe^{-y}}{x!}](https://tex.z-dn.net/?f=P%28X%20%3D%20x%29%20%3D%20%5Cfrac%7By%5Exe%5E%7B-y%7D%7D%7Bx%21%7D)
Where y represents λ (average)
y = 2.3
<em>Probability of renting no more than 1 apartment = Probability of renting no apartment + Probability of renting 1 apartment</em>
<em />
Using probability notations;
![P(X\leq 1) = P(X=0) + P(X =1)](https://tex.z-dn.net/?f=P%28X%5Cleq%201%29%20%3D%20P%28X%3D0%29%20%2B%20P%28X%20%3D1%29)
Solving for P(X = 0) [substitute 0 for x and 2.3 for y]
![P(X = 0) = \frac{2.3^0 * e^{-2.3}}{0!}](https://tex.z-dn.net/?f=P%28X%20%3D%200%29%20%3D%20%5Cfrac%7B2.3%5E0%20%2A%20e%5E%7B-2.3%7D%7D%7B0%21%7D)
![P(X = 0) = \frac{1 * e^{-2.3}}{1}](https://tex.z-dn.net/?f=P%28X%20%3D%200%29%20%3D%20%5Cfrac%7B1%20%2A%20e%5E%7B-2.3%7D%7D%7B1%7D)
![P(X = 0) = e^{-2.3}](https://tex.z-dn.net/?f=P%28X%20%3D%200%29%20%3D%20e%5E%7B-2.3%7D)
![P(X = 0) = 0.10025884372](https://tex.z-dn.net/?f=P%28X%20%3D%200%29%20%3D%200.10025884372)
Solving for P(X = 1) [substitute 1 for x and 2.3 for y]
![P(X = 1) = \frac{2.3^1 * e^{-2.3}}{1!}](https://tex.z-dn.net/?f=P%28X%20%3D%201%29%20%3D%20%5Cfrac%7B2.3%5E1%20%2A%20e%5E%7B-2.3%7D%7D%7B1%21%7D)
![P(X = 1) = \frac{2.3 * e^{-2.3}}{1}](https://tex.z-dn.net/?f=P%28X%20%3D%201%29%20%3D%20%5Cfrac%7B2.3%20%2A%20e%5E%7B-2.3%7D%7D%7B1%7D)
![P(X = 1) =2.3 * e^{-2.3}](https://tex.z-dn.net/?f=P%28X%20%3D%201%29%20%3D2.3%20%2A%20e%5E%7B-2.3%7D)
![P(X = 1) = 2.3 * 0.10025884372](https://tex.z-dn.net/?f=P%28X%20%3D%201%29%20%3D%202.3%20%2A%200.10025884372)
![P(X = 1) = 0.23059534055](https://tex.z-dn.net/?f=P%28X%20%3D%201%29%20%3D%200.23059534055)
![P(X\leq 1) = P(X=0) + P(X =1)](https://tex.z-dn.net/?f=P%28X%5Cleq%201%29%20%3D%20P%28X%3D0%29%20%2B%20P%28X%20%3D1%29)
![P(X\leq 1) = 0.10025884372 + 0.23059534055](https://tex.z-dn.net/?f=P%28X%5Cleq%201%29%20%3D%200.10025884372%20%2B%200.23059534055)
![P(X\leq 1) = 0.33085418427](https://tex.z-dn.net/?f=P%28X%5Cleq%201%29%20%3D%200.33085418427)
![P(X\leq 1) = 0.331](https://tex.z-dn.net/?f=P%28X%5Cleq%201%29%20%3D%200.331)
Hence, the required probability is 0.331