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3 years ago

Solve the equation. n3 = 8

Mathematics

2 answers:

Margaret [11]3 years ago

8 0

Answer:

2.66666667

Step-by-step explanation:

vagabundo [1.1K]3 years ago

6 0

Answer:

I'm pretty sure it's 2

Step-by-step explanation:

You might be interested in

What is the measerment of the missing angle?

Ede4ka [16]

Answer:

80°

Step-by-step explanation:

Since they are vertical angles, they are congruent to each other.

∠r ≅ 80°

3 0

3 years ago

Read 2 more answers

A furniture maker uses the specification 19.88

dimulka [17.4K]

Answer:

The correct answer is:

w-12 20

Explanation:

We first find the average of the two ends of the inequality:

(19.88+20.12)/2 = 40/2 = 20

This will be the number subtracted from w in the inequality.

Now we find the difference between this value and the ends:

20-19.88 = 0.12

20.12 - 20 = 0.12

This will be what our absolute value inequality ends with; the "answer" part, so to speak.

Since this inequality is written in compact form, it must be an "and" inequality; this means the absolute value inequality must be a "less than or equal to."

This gives us

w -12 20

5 0

3 years ago

<img src="https://tex.z-dn.net/?f=%24a%2Ba%20r%2Ba%20r%5E%7B2%7D%2B%5Cldots%20%5Cinfty%3D15%24%24a%5E%7B2%7D%2B%28a%20r%29%5E%7B

riadik2000 [5.3K]

Let

$S_n = \displaystyle \sum_{k=0}^n r^k = 1 + r + r^2 + \cdots + r^n$

where we assume |r| < 1. Multiplying on both sides by r gives

$r S_n = \displaystyle \sum_{k=0}^n r^{k+1} = r + r^2 + r^3 + \cdots + r^{n+1}$

and subtracting this from $S_n$ gives

$(1 - r) S_n = 1 - r^{n+1} \implies S_n = \dfrac{1 - r^{n+1}}{1 - r}$

As n → ∞, the exponential term will converge to 0, and the partial sums $S_n$ will converge to

$\displaystyle \lim_{n\to\infty} S_n = \dfrac1{1-r}$

Now, we're given

$a + ar + ar^2 + \cdots = 15 \implies 1 + r + r^2 + \cdots = \dfrac{15}a$

$a^2 + a^2r^2 + a^2r^4 + \cdots = 150 \implies 1 + r^2 + r^4 + \cdots = \dfrac{150}{a^2}$

We must have |r| < 1 since both sums converge, so

$\dfrac{15}a = \dfrac1{1-r}$

$\dfrac{150}{a^2} = \dfrac1{1-r^2}$

Solving for r by substitution, we have

$\dfrac{15}a = \dfrac1{1-r} \implies a = 15(1-r)$

$\dfrac{150}{225(1-r)^2} = \dfrac1{1-r^2}$

Recalling the difference of squares identity, we have

$\dfrac2{3(1-r)^2} = \dfrac1{(1-r)(1+r)}$

We've already confirmed r ≠ 1, so we can simplify this to

$\dfrac2{3(1-r)} = \dfrac1{1+r} \implies \dfrac{1-r}{1+r} = \dfrac23 \implies r = \dfrac15$

It follows that

$\dfrac a{1-r} = \dfrac a{1-\frac15} = 15 \implies a = 12$

and so the sum we want is

$ar^3 + ar^4 + ar^6 + \cdots = 15 - a - ar - ar^2 = \boxed{\dfrac3{25}}$

which doesn't appear to be either of the given answer choices. Are you sure there isn't a typo somewhere?

7 0

2 years ago

Which choice shows the following fractions with a common denominator? 3/4 and 5/6

Roman55 [17]

Answer:

9/12 and 10/12

Step-by-step explanation:

The LCD is the smallest number divisible by both 4 and 6, and that is 12.

Thus, 3/4 and 5/6 are equivalent to 9/12 and 10/12 .

Next time, kindly share the answer choices. Thank you.

4 0

3 years ago

REY [17]

The true statement about the graph of the function f(x) = x3 - 2x2 + 4x – 8 is (B) The function has 1 real zero that occurs 1 time.

<h3>How to determine the true statement</h3>

The function of f(x) is represented as:

$f(x)=x^3-2x^2+4x-8$

Differentiate the function f(x)

$f'(x)=3x^2-4x+4$

Calculate the minimum value using:

$x = -\frac b{2a}$

So, we have:

$x = -\frac {-4}{2*3}$

$x = \frac {2}{3}$

Substitute 2/3 in f'(x)

$f'(2/3)=3*(2/3)^2-4(2/3)+4$

$f'(2/3)=\frac 83$

The value of f'(2/3) is greater than 0.

This means that the function f(x) has 1 real zero, and it occurs once at point (2,0)

Hence, the true statement is (b)