Answer:
The second option (see attached image)
Step-by-step explanation:
You are looking for a box diagram that represents 9 units, and from those, clearly marked sections that contain 3/2 = 1.5 units.The idea is to count how many 1.5 units you have in 9 units.
The in the second diagram you see 9 boxes subdivided in half. Then outlined in red other smaller boxes of length 1.5 units. We can clearly see from the diagram that there are exactly 6 of these smaller 1.5 units red boxes to produce the total 9 unit object.
Answer:
f(9)= -72
g(-9)= 225
Step-by-step explanation:
First put the original equation
f(x)=-7x-9
Next plug in the number f(9)
f(9)=-7(9)-9
After multiply -7(9) which gets you -63
f(9)=-63-9
Then subtract -63-9 which gets you -72
f(9)=-72
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First put the original
g(x)=6x3-23x
Next plug in the number g(-9)
g(-9)=6x3-23(-9)
After multiply 6x3 which gives you 18 then multiply -23(-9)
g(-9)=18+207
then add 18+207 which gives you 225
g(-9)=225
Seconded to the bottomed is symmetric property of equality
bottomed one is substitution property of equality
first one is reflexive property of equality <span />
Ok don’t worry this is a very easy topic
It falls under “gradients of a straight line”
I’ll try my best to explain the question but u can find plenty of videos online (Fuse School or Cognito) explaining the topic in detail.
Gradient means slope or how steep a line is.
To find the gradient we use the formula
(Change in y) / (change in x)
*Step 1*
Choose any two coordinates (exact) of the line from the graph
For line 1 let’s take
(2,4) (-3,4)
Now from this
the change in y= (4-4) = 0
the change in x = (-3-2) = -5
So the gradient = 0/-5 = 0
*Now this makes sense because a straight horizontal line has no slope and thus has a gradient of zero. So even without all the calculation we can figure this out easily.
Now for line 2 let’s take the coordinates:
(-3,1) (-3,3)
The change in y= (3-1) = 2
The change in x = (-3- -3) = 0
So gradient = 2/0 = “Undefined”
*The gradient of vertical straight line is always undefined (no gradient)*
*The gradient of horizontal straight lines is always 0*
Hope this helped and best of luck for your exams!
