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notsponge [240]
2 years ago
14

Build Your Math Skills 2B, Round decimals to the nearest hundredth (0.01): 1223.075

Mathematics
1 answer:
Tpy6a [65]2 years ago
7 0

Answer: 1223.07

Step-by-step explanation: you don't round up

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The wind speed s (in miles per hour) is related to the distance (in miles) the tornado travels by the equation s = 93log d + 65.
Vesnalui [34]

Answer:

The distance the tornado traveled was approximately 205 miles.

Step-by-step explanation:

The equation representing the relationship between the wind speed (in miles per hour) and the distance the tornado travels (in miles) is:

s=93\log d+65

Compute the value of <em>d</em> for <em>s</em> = 280 as follows:

        s=93\log d+65

     280=93\log d+65

93\log d=280-65\\93\log d=215

   \log d=2.312\\

        d=10^{2.312}\\d=205.035\\d\approx 205

Thus, the distance the tornado traveled was approximately 205 miles.

7 0
3 years ago
Explain the circumstances for which the interquartile range is the preferred measure of dispersion. What is an advantage that th
KatRina [158]

Answer:

Explain the circumstances for which the interquartile range is the preferred measure of dispersion

Interquartile range is preferred when the distribution of data is highly skewed (right or left skewed) and when we have the presence of outliers. Because under these conditions the sample variance and deviation can be biased estimators for the dispersion.

What is an advantage that the standard deviation has over the interquartile​ range?

The most important advantage is that the sample variance and deviation takes in count all the observations in order to calculate the statistic.

Step-by-step explanation:

Previous concepts

The interquartile range is defined as the difference between the upper quartile and the first quartile and is a measure of dispersion for a dataset.

IQR= Q_3 -Q_1

The standard deviation is a measure of dispersion obatined from the sample variance and is given by:

s=\sqrt{\frac{\sum_{i=1}^n (X_i -\bar X)^2}{n-1}}

Solution to the problem

Explain the circumstances for which the interquartile range is the preferred measure of dispersion

Interquartile range is preferred when the distribution of data is highly skewed (right or left skewed) and when we have the presence of outliers. Because under these conditions the sample variance and deviation can be biased estimators for the dispersion.

What is an advantage that the standard deviation has over the interquartile​ range?

The most important advantage is that the sample variance and deviation takes in count all the observations in order to calculate the statistic.

8 0
3 years ago
Solve (x – 3)2 = 49. Select the values of x. –46 -4 10 52
Fudgin [204]

Answer: x = 55/2

Step-by-step explanation: (x)(2) (-3)(2) = 49                                                       2x-6+6 = 49+6                                                                                                               2x/2 = 55/2                                                                                                                   x = 55/2

I know that my answer isn't a choice for one of the values of x but that's the result that I got when I solved (x–3)2 = 49.

6 0
2 years ago
I’ll give points + brainslist, if you don’t know don’t bother answering (:
Damm [24]
C. 35 because c. Is the right answer just trust me ok
8 0
3 years ago
Solve the equation.
Zina [86]

Answer:

x=5

Step-by-step explanation:

esa es la respuesta correcta

7 0
2 years ago
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