Question

Solve (2x^4+6x-5)/(x^2+4) using long division Will mark brainliest

Answer 1

Answer:

$\frac{2x^4+6x-5}{x^2+4}=2x^2-8+\frac{6x+27}{x^2+4}$

Step-by-step explanation:

We want to solve $\frac{2x^4+6x-5}{x^2+4}$ using long division.

We carry out the long division as shown in the attachment.

This implies that:

$\implies \frac{2x^4+6x-5}{x^2+4}=2x^2-8+\frac{6x+27}{x^2+4}$