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Jlenok [28]
3 years ago
9

Solve (2x^4+6x-5)/(x^2+4) using long division Will mark brainliest

Mathematics
1 answer:
bija089 [108]3 years ago
5 0

Answer:

\frac{2x^4+6x-5}{x^2+4}=2x^2-8+\frac{6x+27}{x^2+4}

Step-by-step explanation:

We want to solve \frac{2x^4+6x-5}{x^2+4} using long division.

We carry out the long division as shown in the attachment.

This implies that:

\implies \frac{2x^4+6x-5}{x^2+4}=2x^2-8+\frac{6x+27}{x^2+4}

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3 years ago
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