By concepts of polynomials and systems of linear equations, the constants c and d of the expression p(x) = x⁴ - 5 · x³ - 7 · x² + c · x + d are 29 and 30.
<h3>How to determine the missing coefficients of a quartic equation</h3>
A value x is a root of a polynomial if and only if p(x) = 0. We must replace the given equation with the given roots and solve the resulting system of <em>linear</em> equations:
(- 1)⁴ - 5 · (- 1)³ - 7 · (- 1)² + (- 1) · c + d = 0
- c + d = 1 (1)
3⁴ - 5 · 3³ - 7 · 3² + 3 · c + d = 0
3 · c + d = 117 (2)
The solution of this system is c = 29 and d = 30.
By concepts of polynomials and systems of linear equations, the constants c and d of the expression p(x) = x⁴ - 5 · x³ - 7 · x² + c · x + d are 29 and 30.
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A 40 degree angle: go from the right positive side of the x-axis and go left (left is positive degrees) forty degrees, which is a little less than halfway in quadrant 1.
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Answer:
-2/9
Step-by-step explanation:
first you are going to distrubute 2/5, so 2/5 times x is 2/5x and 2/5 times -2 is -4/5
next you set up the problem with those two answers which gives you:
2/5x - 4/5 = 4x
then multiply both sides of the equation by 5: 2x-4=20x
next move the constant to the right side and chnage the sign: 2x=20x+4
then combine like terms: -18x=4
after that divide both sides of the equation by -18: -2/9
so x= -2/9
