Answer:
n > 96
Therefore, the number of samples should be more than 96 for the width of their confidence interval to be no more than 10mg
Step-by-step explanation:
Given;
Standard deviation r= 25mg
Width of confidence interval w= 10mg
Confidence interval of 95%
Margin of error E = w/2 = 10mg/2 = 5mg
Z at 95% = 1.96
Margin of error E = Z(r/√n)
n = (Z×r/E)^2
n = (1.96 × 25/5)^2
n = (9.8)^2
n = 96.04
n > 96
Therefore, the number of samples should be more than 96 for the width of their confidence interval to be no more than 10mg
Answer:
3x(x - 4)(x + 2)
Step-by-step explanation:
Given
3x³ - 6x² - 24x ← factor out common factor of 3x from each term
= 3x(x² - 2x - 8) ← factor the quadratic
Consider the factors of the constant term (- 8) which sum to give the coefficient of the x- term.
The factors are - 4 and + 2, since
- 4 × 2 = - 8 and - 4 + 2 = - 2, thus
x² - 2x - 8 = (x - 4)(x + 2) and
3x³ - 6x² - 24x = 3x(x - 4)(x + 2)
2/3 is 266.66% of 2/4.
(2/3)(1/4)=(2/3)(4/1)=8/3=2 2/3=2.6666=266.66
hope this helps!!
Well, the keyword here is One of the performers insist on being the last.
So, the amount of performers that we can arrange freely is 7 performers.
Different ways we can schedule their appearance is :
7 ! = 7 x 6 x 5 x 4 x 3 x 2 x 1
= 5040
hope this helps
Answer:
D
Step-by-step explanation:
To find the rate of increase all you have to do is take one of the data sets to see that every two months its charge time increases by 15 minutes or 7.5 minutes every month.
