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Harrizon [31]
3 years ago
4

Which expression is equivalent to RootIndex 4 StartRoot StartFraction 24 x Superscript 6 Baseline y Over 128 x Superscript 4 Bas

eline y Superscript 5 Baseline EndFraction EndRoot? Assume x not-equals 0 and y
StartFraction RootIndex 4 StartRoot 3 EndRoot Over 2 x squared y EndFraction
StartFraction x (RootIndex 4 StartRoot 3 EndRoot) Over 4 y squared EndFraction
StartFraction RootIndex 4 StartRoot 3 EndRoot Over 4 x y squared EndFraction
StartFraction RootIndex 4 StartRoot 3 x squared EndRoot Over 2 y EndFraction
Mathematics
2 answers:
Vanyuwa [196]3 years ago
5 0

Answer:

The expression is equivalent toA=\sqrt[4]{\frac{24\ x^{6}\ y}{128\ x^{4}\ y^{5}}} is  \frac{\sqrt[4]{3}}{2}}\times \frac{\sqrt{x}}{y}.

Step-by-step explanation:

The expression provided is:

A=\sqrt[4]{\frac{24\ x^{6}\ y}{128\ x^{4}\ y^{5}}}

Simplify the expression <em>A</em> as follows:

A=\sqrt[4]{\frac{24\ x^{6}\ y}{128\ x^{4}\ y^{5}}}

   =\sqrt[4]{\frac{24}{128}\times x^{(6-4)}\times y^{(1-5)}}\\\\=\sqrt[4]{\frac{3}{16}\times x^{2}\times y^{-4}}\\\\=[\frac{3}{16}\times x^{2}\times y^{-4}]^{1/4}\\\\=[\frac{3}{16}]^{1/4}\times x^{(2\times (1/4))}\times y^{(-4\times (1/4))}\\\\=\frac{\sqrt[4]{3}}{2}}\times x^{1/2}\times y^{-1}\\\\=\frac{\sqrt[4]{3}}{2}}\times \frac{\sqrt{x}}{y}

Thus, the expression is equivalent toA=\sqrt[4]{\frac{24\ x^{6}\ y}{128\ x^{4}\ y^{5}}} is  \frac{\sqrt[4]{3}}{2}}\times \frac{\sqrt{x}}{y}.

horrorfan [7]3 years ago
3 0

Answer:

The answer is D, I just took it on edgen.  Known as RootIndex 4 StartRoot 3 x squared EndRoot Over 2 y       <em>or        </em> 4 root 3x^2/ 2y

Step-by-step explanation:

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