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3 years ago

Which equation is equivalent to 2x+3y=12

Mathematics

2 answers:

Umnica [9.8K]3 years ago

5 0

Answer:

Step-by-step explanation:

You could multiply it by 2.

4x+6y=24

4vir4ik [10]3 years ago

3 0

some possible equations equivalent to 2x+3y=12 would be:

y=−2x+12/3

written form:

y= negative 2x plus 12 over/divided by 3

y=−2/3x+4

written form:

y= negative 2 over/divided by 3x plus 4

y=4−2/3x

written form:

y= 4 minus 2 over/divided by 3x

y=12−2x/3

written form:

y= 12 minus 2x over/divided by 3

those are all i could think of! Hope this helped :)

If its too complicated comment and ill try to simplify it. remember ITS NEVER WRONG TO ASK QUESTIONS!!!

You might be interested in

Find the dimensions of the open rectangular box of maximum volume that can be made from a sheet of cardboard 21 in. by 12 in. by

a_sh-v [17]

Answer:

Dimension of the box is $16.1\times 7.1\times 2.45$

The volume of the box is 280.05 in³.

Step-by-step explanation:

Given : The open rectangular box of maximum volume that can be made from a sheet of cardboard 21 in. by 12 in. by cutting congruent squares from the corners and folding up the sides.

To find : The dimensions and the volume of the box?

Solution :

Let h be the height of the box which is the side length of a corner square.

According to question,

A sheet of cardboard 21 in. by 12 in. by cutting congruent squares from the corners and folding up the sides.

The length of the box is $L=21-2h$

The width of the box is $W=12-2h$

The volume of the box is $V=L\times W\times H$

$V=(21-2h)\times (12-2h)\times h$

$V=(21-2h)\times (12h-2h^2)$

$V=252h-42h^2-24h^2+4h^3$

$V=4h^3-66h^2+252h$

To maximize the volume we find derivative of volume and put it to zero.

$V'=12h^2-132h+252$

$0=12h^2-132h+252$

Solving by quadratic formula,

$h=\frac{-b\pm\sqrt{b^2-4ac}}{2a}$

$h=\frac{-(-132)\pm\sqrt{132^2-4(12)(252)}}{2(12)}$

$h=\frac{132\pm72.99}{24}$

$h=2.45,8.54$

Now, substitute the value of h in the volume,

$V=4h^3-66h^2+252h$

When, h=2.45

$V=4(2.45)^3-66(2.45)^2+252(2.45)$

$V\approx 280.05$

When, h=8.54

$V=4(8.54)^3-66(8.54)^2+252(8.54)$

$V\approx -170.06$

Rejecting the negative volume as it is not possible.

Therefore, The volume of the box is 280.05 in³.

The dimension of the box is

The height of the box is h=2.45

The length of the box is $L=21-2(2.45)=16.1$

The width of the box is $W=12-2(2.45)=7.1$

So, Dimension of the box is $16.1\times 7.1\times 2.45$

6 0

3 years ago

A line represented by y = 2x − 3 and a line perpendicular to it intersect at R(2, 1). What is the equation of the perpendicular

neonofarm [45]

Answer:

y = -1/2x + 2

Step-by-step explanation:

y = 2x - 3. The slope here is 2. A perpendicular line will have a negative reciprocal slope. To find the negative reciprocal, just flip the slope and change the sign.

slope = 2 or 2/1.....flip it.....1/2....change the sign...-1/2. So our perpendicular line will have a slope of -1/2.

y = mx + b

slope(m) = - 1/2

(2,1)....x = 2 and y = 1

now we sub and find b, the y intercept

1 = -1/2(2) + b

1 = -1 + b

1 + 1 = b

2 = b

so ur equation is : y = -1/2x + 2 <===

and u can check it with ur points....(2,1)

y = 2x - 3

1 = 2(2) - 3

1 = 4 - 3

1 = 1 (yep...it checks out)

8 0

3 years ago

I really need help with 1 and 2 please help me I begg you

Lera25 [3.4K]

1.) So 1/5 of a relay, or r, is 3/4 of a mile.
1/5r = 3/4
Multiply 5 on both sides of the equation.

r = 15/4

The relay was 15/4 of a mile or 3 3/4 of a mile.

2.) No, it is not because the sum of the digits are not divisible by 3.

Hope this helps! :)

7 0

3 years ago

Read 2 more answers

2. If you pay a one-time fee of $30, you can

VikaD [51]

Answer:

Kindly check explanation

Step-by-step explanation:

Given that :

One time fee = $30

Reduced price of ticket after one time fee payment = $17

Regular ticket cost = $25

Write an inequality that can be used to determine the number of reduced price concert tickets you would need to purchase in order for the total cost to be less expensive than the same number of regular tickets

Let the number of tickets needed to purchase = t

Reduced ticket = 30 + 17t

Regular ticket = 25t

30 + 17t < 25t

30 < 25t - 17t

30 < 8t

30/8 < 8t/8

3.75 < t

t > 3.75

Hence number of ticket must be greater than 3.75

t = 4

5 0