This happens for
25. En cada par de triangulos, las marcas iguales indican elementos congruentes. ¿Que par de triangulos es congruentre segun el
criterio LAL? justifica 26.indica cual criterio se debe usar para determinar la congruencia de cada pareja de triangulos.
1 answer:
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Answer:
{-1, 1/2, 2/3, 1}
Step-by-step explanation:
I find a graphing calculator to be a most useful tool for problems like this. (See attached.)
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First of all, observe that the constant is -2, so 0 is not a zero.
It is often useful to look at the sum of coefficients. Here, that is 0, indicating 1 is a zero.
You can divide that out, or simply continue by looking at the sum of coefficients with odd-degree terms negated. Then you have 6 +7 -4 -7 -2 = 0, indicating -1 is also a zero.
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At this point, it can be useful to divide out the factors you know. The synthetic division tableaus attached show that work. First is division by (x+1), then by (x -1).
The result of doing that is the quadratic ...
6x^2 -7x +2 = 0
This can be factored ...
(6x^2 -3x) -(4x -2) = 0 . . . . . . rewrite -7x and group term pairs
3x(2x -1) -2(2x -1) = 0 . . . . . . . factor each pair
(3x -2)(2x -1) = 0 . . . . . . the factorization of the remaining quadratic
The zeros of this are the values of x that make the factors zero: 2/3 and 1/2.
The zeros of the given function f(x) are x ∈ {-1, 1/2, 2/3, 1}.
