Answer:
6.5 x 10^6 To answer this question, you need to divide the mass of the sun by the mass of mercury. So 2.13525 x 10^30 / 3.285 x 10^23 = ? To do the division, divide the mantissas in the normal fashion 2.13525 / 3.285 = 0.65 And subtract the exponents. 30 - 23 = 7 So you get 0.65 x 10^7 Unless the mantissa is zero, the mantissa must be greater than or equal to 0 and less than 10. So multiply the mantissa by 10 and then subtract 1 from the exponent, giving 6.5 x 10^6 So the sun is 6.5 x 10^6 times as massive as mercury.
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Answer:
the answer would be -13n-23
Step-by-step explanation:
first you want to distribute the brackets
-7(2+n) = -14-7n
+(-9-6n)
-9-6n
-14-7n-9-6n
combine the n value with an n value and an integer that doesn't have an n value
-7n-6n-14-9
= -13n-23
Answer:
Step-by-step explanation:
Jack's method is equivalent because of the "law of commutative property", which means that multiplication problems have the same result no matter the order.
2x5 is the same as 5x2
p=36
because 15 is 3 times 5 so just multiply the perimeter
Answer: A. The first one
Step-by-step explanation: