Answer:
51,111%
Step-by-step explanation:
We know that 45% have a dog but no cat. While 23% have both a dog and a cat.
Then Pr(X has cat|X has dog) = Pr(X has dog and cat)/Pr(X has dog)
= Pr(X has dog and cat)/Pr(X has dog) = 0.23/0.45 = 0.51 ≈ 51,111%
The probability that a student’s family owns a cat if the family owns a dog is 51,111%
The first digit of the quotient is the first number of the answer of your division problem. the answer is 2
Answer:
Step-by-step explanation:
f'(x)=-sin x

c=0∈(-π/3,π/3)
The decimal is .39024..., or rounded to percent it is 39%